In Exercises 1–8, parametric equations and a value for the parame...

Question

In Exercises 1–8, parametric equations and a value for the parameter t are given. Find the coordinates of the point on the plane curve described by the parametric equations corresponding to the given value of t.

x = 3 − 5t, y = 4 + 2t; t = 1

Accepted Answer

Welcome back everyone. In this problem, we want to determine the coordinates of the point on the plane curve represented by the parametric equations. X equals seven minus nine U and Y equals six plus four U where U equals three for our answer choices, A is negative 18 20 B is negative 2018, C is 34 negative six and D is negative 6 34. Now, what do we know? Well, we know that both of these are parametric equations. And what that really means is just that we have some fancy looking equation where every coordinate on it is related by that common parameter. U. So if we substitute that value of U that we know into our equations, then we'll be able to solve for the values of X and Y. So I'm going to let X be my first equation, X equals seven minus nine U and my second equation is going to be Y equals six plus four U. So I'm going to use both to sulfur X and Y. So firstly solving for X, then my equation will be X equals seven minus nine, multiplied by U no, U is three. So that's nine, multiplied by three, nine, multiplied by three is 27 and seven minus is negative 20. That's my value for eggs. Likewise, solving for why Y equals six plus four, U so that is going to become six plus four, multiplied by three, four, multiplied by three is 12 and six plus 12 is 18. Therefore, X equals negative 20 Y equals 18, which means my answer is choice. B thanks a lot for watching. I hope this video helped.

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In Exercises 1–8, parametric equations and a value for the parameter t are given. Find the coordinates of the point on the plane curve described by the parametric equations corresponding to the given value of t. x = 3 − 5t, y = 4 + 2t; t = 1