Light Bulbs in Series and in Parallel. Two light bulbs have constant resistances of 400Ω and 800Ω. The two light bulbs are now connected in parallel across the 120-V line. Find (e) the power dissipated in each bulb.

Video transcript

Hey everyone in this problem. We have an electric appliance that has two heating coils resistance 9. and 14.4 ohms. The two coils have a parallel connection and are powered by a volt power source were asked to determine the power output of each coil. Now, let's recall that the power output P. Is equal to the voltage V times the current. I. Now we're giving information about the voltage V. And the resistance are we don't have information about the current. I but let's recall through OEMs Law, we can relate the I. And R. Okay, we know that the current i is going to be equal to the voltage V divided by the resistance are and so we can write the power output P is V squared over. R. All right now, we're trying to figure out the power output of each of these coils. So the power output of the coil with resistance 9.6. So we're gonna call it P 9.6 is going to be equal to the voltage, which we know is 100 and 10 volts squirt Divided by the resistance which is 9.60ms. And this is going to give us a power output of 1,260. repeated watts. Okay, we have volts squared over. We get the unit of watts for power. We're gonna do the same thing with the second coil. So the power output for the coil with a resistance of 14.4 arms will call it P 14.4 is going to be, we have the same voltage 110 volts and we have a resistance of 14.4 modems given in the problem, which gives us a power output of 840.277 repeated watts. And so the power outputs, okay, for the first coil, that 9.6 ohm coil is 1260.4166 watts. The power output for the second coil with resistance 14.4 OEMs is going to be 840.277 watts. And so we have answer choice D. That's it for this one. Thanks everyone for watching. See you in the next video.