Light Bulbs in Series and in Parallel. Two light bulbs have constant resistances of 400Ω and 800Ω. The two light bulbs are now connected in parallel across the 120-V line. Find (d) the current through each bulb.

Video transcript

Hey everyone, Welcome back in this problem. We have a room heater that has two heating coils connected in parallel. The resistance is R one equals 14.4 arms. And R two is equal to 10.3 on the power line provides 100 and 10 volt potential difference and were asked to determine the current through each coil. Mhm. Now we're in parallel And recall that in parallel the potential difference is going to be the same across each element. Okay, so that potential difference of 110V is going to apply to both coils. They are both elements. Now we're trying to find a current, we have information about the voltage or the potential. Okay. And we have information about the resistance. So let's recall through OEMs Law that we have I is equal to V over R. And we're gonna take this to be I one R one. Okay. The first current related to the first resistor And I two is equal to V over R two. Now we know our voltages, we know our resistance. So this is just a matter of using these equations with those values. So our voltage or potential difference. 110V divided by our resistance are 1.14.40ems. Okay, and this is going to give us a current of 7. amps. Okay, Through that first resistor. Through that first quail and for the second one we have the potential difference of 110 volts divided by the resistance of 10.3 OEMs which gives us a current of 10.68 amperes, approximately. Okay, so we have our first current 7.6388 amperes and our second of 10.68 amperes. And that is going to correspond with answer choice E. That's it for this one. Thanks everyone for watching. See you in the next video.