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Ch 28: Sources of Magnetic Field
Chapter 28, Problem 28

A solenoid is designed to produce a magnetic field of 0.0270 T at its center. It has radius 1.40 cm and length 40.0 cm, and the wire can carry a maximum current of 12.0 A. (a) What minimum number of turns per unit length must the solenoid have?

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Identify the formula for the magnetic field at the center of a solenoid, which is given by B = \( \mu_0 \cdot n \cdot I \), where \( B \) is the magnetic field, \( \mu_0 \) is the permeability of free space (\( 4\pi \times 10^{-7} \, T \cdot m/A \)), \( n \) is the number of turns per unit length, and \( I \) is the current.
Rearrange the formula to solve for \( n \), the number of turns per unit length. This gives \( n = \frac{B}{\mu_0 \cdot I} \).
Substitute the values for \( B \) (0.0270 T) and \( I \) (12.0 A) into the rearranged formula.
Calculate \( n \) using the substituted values and the constant \( \mu_0 \).
Ensure that the calculated value of \( n \) meets the condition of being the minimum number of turns per unit length required to produce the specified magnetic field.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Magnetic Field in a Solenoid

The magnetic field inside a long solenoid is given by the formula B = μ₀(nI), where B is the magnetic field strength, μ₀ is the permeability of free space, n is the number of turns per unit length, and I is the current. This relationship shows how the magnetic field strength is directly proportional to both the current flowing through the wire and the density of the turns.
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Turns per Unit Length

Turns per unit length (n) refers to the number of loops of wire in a solenoid per unit of length. It is a crucial factor in determining the strength of the magnetic field produced by the solenoid. To find n, one can rearrange the magnetic field formula to n = B / (μ₀I), allowing for the calculation of the necessary turns to achieve a desired magnetic field.
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Permeability of Free Space

The permeability of free space (μ₀) is a physical constant that describes how a magnetic field interacts with a vacuum. Its value is approximately 4π × 10⁻⁷ T·m/A. This constant is essential in the calculation of magnetic fields in solenoids and other electromagnetic devices, as it influences the relationship between magnetic field strength, current, and turns per unit length.
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Related Practice
Textbook Question
As a new electrical technician, you are designing a large solenoid to produce a uniform 0.150-T magnetic field near the center of the solenoid. You have enough wire for 4000 circular turns. This solenoid must be 55.0 cm long and 2.80 cm in diameter. What current will you need to produce the necessary field?
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Textbook Question
A solid conductor with radius a is supported by insulating disks on the axis of a conducting tube with inner radius b and outer radius c (Fig. E28.43). The central conductor and tube carry equal currents I in opposite directions. The currents are distributed uniformly over the cross sections of each conductor. Derive an expression for the magnitude of the magnetic field (b) at points outside the tube (r > c).
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Textbook Question
A 15.0-cm-long solenoid with radius 0.750 cm is closely wound with 600 turns of wire. The current in the windings is 8.00 A. Compute the magnetic field at a point near the center of the solenoid.
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Textbook Question
A solenoid is designed to produce a magnetic field of 0.0270 T at its center. It has radius 1.40 cm and length 40.0 cm, and the wire can carry a maximum current of 12.0 A. (b) What total length of wire is required?
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Textbook Question
Currents in dc transmission lines can be 100 A or higher. Some people are concerned that the electromagnetic fields from such lines near their homes could pose health dangers. For a line that has current 150 A and a height of 8.0 m above the ground, what magnetic field does the line produce at ground level? Express your answer in teslas and as a percentage of the earth's magnetic field, which is 0.50 G. Is this value cause for worry?
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Textbook Question
Four, long, parallel power lines each carry 100-A currents. A cross-sectional diagram of these lines is a square, 20.0 cm on each side. For each of the three cases shown in Fig. E28.25

, calculate the magnetic field at the center of the square.
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