The heating element of an electric dryer is rated at 4.1 kW when connected to a 240-V line. (b) What is the resistance of the dryer's heating element at its operating temperature?

Video transcript

Hi everyone today we are going to determine the resistance of an electric kettle at an operating condition of 1200 watt and 220 fold. So it is given that the power that is that is operating at is 1200 watt and the potential difference or the voltage is 220 fold and recall the power can actually be calculated using this formula right here and the I and V. And the resistance is actually correlated with one another to OEMs law because we only know what the voltage is and we want to find what the resistance is. You want to substitute the eye here so that it is going to be in terms of fee and are using homes law. So rearranging things, I can be represented by a V divided by the R. And substituting this formula into here. Then we will have P equals fee over. Are multiplied by v. Soapy will equals two fi squared over R. With P being the power of V being defaulted and are being the resistance with this. We can then solve for R which is going to be equals to v squared over over. P. Now we have the V which is 2020 we have the P which is 1200. So we can actually solve for this problem. So the fee is going to be 220 fold squared. The P is going to be 1200 what? So essentially um solving for this, we will be able to solve for R which is going to be 40. and that will essentially be the answer to this problem, which is going to be re corresponding to option D. So the resistance of the electric cattle at this operating conditions is going to be 40.3. Oh, if you guys are still confused on this, there are other lessons, video lessons that you guys can check out. That will be very useful, and hopefully you will be able to gain more understanding on this particular topic. Thank you.