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Ch 25: Current, Resistance, and EMF
Chapter 25, Problem 25

In household wiring, copper wire 2.05 mm in diameter is often used. Find the resistance of a 24.0-m length of this wire.

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1
Calculate the cross-sectional area, A, of the wire using the formula for the area of a circle: A = \pi (d/2)^2, where d is the diameter of the wire.
Find the resistivity, \( \rho \), of copper from a reference table. Resistivity is a material-specific property that quantifies how strongly a material opposes the flow of electric current.
Use the formula for resistance, R, of a uniform cylindrical conductor: R = \( \rho \frac{L}{A} \), where L is the length of the wire and A is the cross-sectional area calculated in step 1.
Substitute the values of \( \rho \), L, and A into the resistance formula to calculate the resistance of the wire.
Ensure the units are consistent when performing the calculations (e.g., converting diameters from millimeters to meters if necessary).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Resistance

Resistance is a measure of the opposition to the flow of electric current in a conductor. It is determined by the material's properties, its length, and its cross-sectional area. The formula for resistance (R) is given by R = ρ(L/A), where ρ is the resistivity of the material, L is the length of the conductor, and A is the cross-sectional area.
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Resistivity

Resistivity is a fundamental property of materials that quantifies how strongly they resist electric current. It is denoted by the symbol ρ and is measured in ohm-meters (Ω·m). Different materials have different resistivities; for example, copper has a low resistivity, making it an excellent conductor for electrical applications.
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Cross-sectional Area

The cross-sectional area of a wire is the area of a slice taken perpendicular to its length. For a circular wire, it can be calculated using the formula A = π(d/2)², where d is the diameter. The cross-sectional area is crucial in determining the resistance of the wire, as a larger area allows more current to flow, reducing resistance.
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