An idealized ammeter is connected to a battery as shown in Fig. E25.28

. Find (b) the current through the 4.00-Ω resistor.

Video transcript

Hi everyone today we are going to determine the current to the 10. Her sister. When the circuit is constructed from an ideal and meter, which is shown in this particular circuit down below. So the circuit that we have here have a 10 on her sister, which is the one that we want to look at. So the way we want to solve for this problem is to recall and use the logic of OEMs Law Home slaw if you recall it well it goes to fee equals I. R. And rearranging this the eye, which is the one V. One is going to equals to feed over. All. Right. So in this particular example, the meter here, I'm gonna indicate it with an A actually acts like a short circuit across The 10 member sister. Therefore because of this short circuit here, the potential difference three because of short circuit Across the resistor is then going to be zero. Sophie equal zero. Fall across the 10 ohm resistor because of that. We can actually plot this value into this formula here. So the I will equals to feed over R. And with a V. Of zero. So the eye is then going to be zero. So that will be the answer to this problem here, which is done. Going to be option E. Right, just like so alright, if you guys are still confused on this particular problem, make sure to check out our other videos regarding this topic. And yeah, that will be all for this problem. Thank you