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Ch 16: Sound & Hearing
Chapter 16, Problem 16

The siren of a fire engine that is driving northward at 30.0 m>s emits a sound of frequency 2000 Hz. A truck in front of this fire engine is moving northward at 20.0 m>s. (b) What wavelength would this driver measure for these reflected sound waves?

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Step 1: Calculate the frequency of the sound as heard by the truck driver using the Doppler Effect formula for sound moving towards an observer. The formula is: f' = f * (v + v_o) / (v - v_s), where f is the original frequency, v is the speed of sound in air (approximately 343 m/s), v_o is the speed of the observer (truck driver), and v_s is the speed of the source (fire engine).
Step 2: Substitute the given values into the formula: f = 2000 Hz, v = 343 m/s, v_o = 20.0 m/s, and v_s = 30.0 m/s. Calculate the new frequency f' that the truck driver hears.
Step 3: Use the relationship between speed, frequency, and wavelength to find the wavelength heard by the truck driver. The formula is: \( \lambda = \frac{v}{f'} \), where \( \lambda \) is the wavelength, v is the speed of sound, and f' is the frequency calculated in step 2.
Step 4: Substitute the values of v and f' into the wavelength formula to calculate the wavelength \( \lambda \) that the truck driver would measure for the sound waves.
Step 5: The calculated wavelength \( \lambda \) is the wavelength of the sound as measured by the truck driver.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Doppler Effect

The Doppler Effect describes the change in frequency or wavelength of a wave in relation to an observer moving relative to the source of the wave. When the source of sound moves towards an observer, the frequency increases, leading to a shorter wavelength. Conversely, if the source moves away, the frequency decreases, resulting in a longer wavelength. This effect is crucial for understanding how the frequency of sound changes for the truck driver as the fire engine approaches.
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The Doppler Effect

Wave Speed

Wave speed is the speed at which a wave travels through a medium. For sound waves in air, the speed is approximately 343 m/s at room temperature. The observed wavelength can be calculated using the formula: wavelength = wave speed / frequency. In this scenario, the relative motion of the fire engine and the truck affects the perceived frequency, which in turn influences the wavelength measured by the truck driver.
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Intro to Waves and Wave Speed

Relative Velocity

Relative velocity refers to the velocity of one object as observed from another object. In this problem, both the fire engine and the truck are moving in the same direction, which affects how the sound waves are perceived. The effective speed of sound relative to the truck driver must account for both the speed of sound in air and the speed of the fire engine, allowing for the calculation of the frequency and wavelength of the sound waves reflected back to the truck.
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Related Practice
Textbook Question
A railroad train is traveling at 30.0 m>s in still air. The frequency of the note emitted by the train whistle is 352 Hz. What frequency is heard by a passenger on a train moving in the opposite direction to the first at 18.0 m>s and (a) approaching the first
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Textbook Question
A railroad train is traveling at 30.0 m>s in still air. The frequency of the note emitted by the train whistle is 352 Hz. What frequency is heard by a passenger on a train moving in the opposite direction to the first at 18.0 m>s and(b) receding from the first?
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Textbook Question
The siren of a fire engine that is driving northward at 30.0 m>s emits a sound of frequency 2000 Hz. A truck in front of this fire engine is moving northward at 20.0 m>s. (a) What is the frequency of the siren's sound that the fire engine's driver hears reflected from the back of the truck?
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Textbook Question
The shock-wave cone created by a space shuttle at one instant during its reentry into the atmosphere makes an angle of 58.0° with its direction of motion. The speed of sound at this altitude is 331 m>s. (a) What is the Mach number of the shuttle at this instant
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Textbook Question
Example 16.1 (Section 16.1) showed that for sound waves in air with frequency 1000 Hz, a displacement amplitude of 1.2 * 10-8 m produces a pressure amplitude of 3.0 * 10-2 Pa. (a) What is the wavelength of these waves?
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Textbook Question
A loud factory machine produces sound having a displacement amplitude of 1.00 mm, but the frequency of this sound can be adjusted. In order to prevent ear damage to the workers, the maximum pressure amplitude of the sound waves is limited to 10.0 Pa. Under the conditions of this factory, the bulk modulus of air is 1.42 * 105 Pa. What is the highest-frequency sound to which this machine can be adjusted without exceeding the prescribed limit? Is this frequency audible to the workers?
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