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Ch 14: Periodic Motion
Chapter 14, Problem 14

A building in San Francisco has light fixtures consisting of small 2.35-kg bulbs with shades hanging from the ceiling at the end of light, thin cords 1.50 m long. If a minor earthquake occurs, how many swings per second will these fixtures make?

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1
Identify the type of motion: The bulbs swinging due to the earthquake can be modeled as simple pendulums.
Write down the formula for the period (T) of a simple pendulum: T = 2\pi \sqrt{\frac{L}{g}}, where L is the length of the pendulum and g is the acceleration due to gravity (approximately 9.81 m/s^2).
Substitute the given values into the formula to find the period T. Use L = 1.50 m and g = 9.81 m/s^2.
Calculate the frequency (f) of the pendulum's swings, since frequency is the reciprocal of the period: f = \frac{1}{T}.
The result from the previous step gives you the number of swings per second the light fixtures will make during the earthquake.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Simple Harmonic Motion

Simple Harmonic Motion (SHM) describes the oscillatory motion of an object around an equilibrium position, where the restoring force is directly proportional to the displacement. In this context, the light fixtures can be modeled as pendulums that swing back and forth when disturbed, such as during an earthquake. The frequency of these swings is determined by the mass of the bulbs and the length of the cords.
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Pendulum Frequency

The frequency of a simple pendulum is the number of complete swings it makes per second. It is influenced by the length of the pendulum and the acceleration due to gravity. The formula for the frequency (f) of a simple pendulum is f = 1/(2π) * √(g/L), where g is the acceleration due to gravity and L is the length of the pendulum. This relationship is crucial for calculating how many swings the light fixtures will make.
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Effect of Gravity

Gravity is the force that pulls objects toward the Earth, and it plays a significant role in the motion of pendulums. The acceleration due to gravity (approximately 9.81 m/s² on Earth) affects the speed and frequency of the swings. In the case of the light fixtures, understanding how gravity interacts with the mass of the bulbs and the length of the cords is essential for determining the oscillation frequency during the earthquake.
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Related Practice
Textbook Question
A 0.500-kg mass on a spring has velocity as a function of time given by vx(t) = -(3.60 cm/s) sin[(4.71 rad/s)t - (pi/2)]. What are (a) the period; (b) the amplitude; (c) the maximum acceleration of the mass; (d) the force constant of the spring?
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Textbook Question
You pull a simple pendulum 0.240 m long to the side through an angle of 3.50° and release it. (a) How much time does it take the pendulum bob to reach its highest speed?
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Textbook Question
You pull a simple pendulum 0.240 m long to the side through an angle of 3.50° and release it. (b) How much time does it take if the pendulum is released at an angle of 1.75° instead of 3.50°?
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Textbook Question
A simple pendulum 2.00 m long swings through a maximum angle of 30.0° with the vertical. Calculate its period (a) assuming a small amplitude, and (b) using the first three terms of Eq. (14.35). (c) Which of the answers in parts (a) and (b) is more accurate? What is the percentage error of the less accurate answer compared with the more accurate one?
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Textbook Question
(a) Music. When a person sings, his or her vocal cords vibrate in a repetitive pattern that has the same frequency as the note that is sung. If someone sings the note B flat, which has a frequency of 466 Hz, how much time does it take the person's vocal cords to vibrate through one complete cycle, and what is the angular frequency of the cords?
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Textbook Question
An object is undergoing SHM with period 0.900 s and amplitude 0.320 m. At t = 0 the object is at x = 0.320 m and is instantaneously at rest. Calculate the time it takes the object to go (a) from x = 0.320 m to x = 0.160 m. (b) from x = 0.160 m to x = 0.
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