A machinist is using a wrench to loosen a nut. The wrench is 25.0 cm long, and he exerts a 17.0-N force at the end of the handle at 37° with the handle (Fig. E10.7). (b) What is the maximum torque he could exert with this force, and how should the force be oriented?

Video transcript

Hello everyone. So this problem when tightening the wheel on a bicycle, a cyclist applies a force of 125 newtons on the shaft of the spanner. The forces applied 25 cm from the mud. What is the highest torque that cyclists can produce by applying this force and with what angle with respect to the shaft? The force should be exerted. So we recall the torque is equal to the cross product between the force vector and the radio vector. And this is simply equal to f our signed data. Where F. Is the force exerted? R is the distance from the center of access or rotation. And data is the angle with respect to that access. If we want to maximize this torque and we have the force exerted as a constant and the distance as a constant. The only thing we can change is this date. We know that science data is maximum data is equal to 90 degrees Or 270°. So we can see that the force will be or the torque will be maximum when the forces applied perpendicular to the radio vector. So we can calculate this maximum force by knowing that signed data will or signed 90 at its maximum will be one. So the twerp will just simply be F. Times are And in this case F is 125 newtons And our will be 25 cm or .25 m. And calculating this, we get the torque will be 31. students times meters is perpendicular. But his answer choice B themselves have a great day.