Skip to main content
Ch 10: Dynamics of Rotational Motion
Chapter 10, Problem 10

A machinist is using a wrench to loosen a nut. The wrench is 25.0 cm long, and he exerts a 17.0-N force at the end of the handle at 37° with the handle (Fig. E10.7). (b) What is the maximum torque he could exert with this force, and how should the force be oriented?A wrench applying a 17.0 N force at 37° to loosen a nut, 25.0 cm long.

Verified step by step guidance
1
Identify the given values: the length of the wrench (r) is 25.0 cm (0.25 m), the force (F) is 17.0 N, and the angle (θ) between the force and the handle is 37°.
Recall the formula for torque (τ): τ = r * F * sin(θ).
Substitute the given values into the torque formula: τ = 0.25 m * 17.0 N * sin(37°).
Calculate the sine of the angle: sin(37°).
Multiply the values together to find the torque: τ = 0.25 m * 17.0 N * sin(37°).

Verified Solution

Video duration:
5m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?