Vector A is 2.80 cm long and is 60.0° above the x-axis in the first quadrant. Vector B is 1.90 cm long and is 60.0° below the x-axis in the fourth quadrant (Fig. E1.35). Use components to find the magnitude and direction of (b) A - B In each case, sketch the vector addition or subtraction and show that your numerical answers are in qualitative agreement with your sketch.
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Step 1: Break down Vector A into its x and y components. Use the formulas: A_x = A * cos(θ) and A_y = A * sin(θ), where A = 2.80 cm and θ = 60.0°.
Step 2: Break down Vector B into its x and y components. Use the formulas: B_x = B * cos(θ) and B_y = B * sin(θ), where B = 1.90 cm and θ = -60.0°.
Step 3: Calculate the components of the resultant vector (A - B) by subtracting the components of B from the components of A. Use the formulas: (A - B)_x = A_x - B_x and (A - B)_y = A_y - B_y.
Step 4: Determine the magnitude of the resultant vector (A - B) using the Pythagorean theorem: |A - B| = sqrt((A - B)_x^2 + (A - B)_y^2).
Step 5: Find the direction of the resultant vector (A - B) by calculating the angle θ with respect to the x-axis using the formula: θ = arctan((A - B)_y / (A - B)_x).
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