Skip to main content
Ch 09: Work and Kinetic Energy
Chapter 9, Problem 9

A pile driver lifts a 250 kg weight and then lets it fall onto the end of a steel pipe that needs to be driven into the ground. A fall from an initial height of 1.5 m drives the pipe in 35 cm. What is the average force that the weight exerts on the pipe?

Verified step by step guidance
1
Calculate the potential energy (PE) of the weight at the initial height using the formula PE = mgh, where m is the mass, g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height.
Assume that all the potential energy is converted into work done on the pipe when the weight hits it. The work done (W) on the pipe is equal to the initial potential energy.
The work done can also be expressed as W = Fd, where F is the average force exerted by the weight on the pipe, and d is the distance the pipe is driven into the ground.
Rearrange the equation W = Fd to solve for the average force, F. This gives F = W/d.
Substitute the expression for W from step 2 and the value of d (distance the pipe is driven into the ground, converted into meters) into the equation from step 4 to find the average force.

Verified Solution

Video duration:
4m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Gravitational Potential Energy

Gravitational potential energy (GPE) is the energy an object possesses due to its position in a gravitational field. It is calculated using the formula GPE = mgh, where m is mass, g is the acceleration due to gravity (approximately 9.81 m/s²), and h is the height above the ground. In this scenario, the weight of the pile driver has gravitational potential energy when lifted to 1.5 m, which is converted to kinetic energy as it falls.
Recommended video:
Guided course
06:35
Gravitational Potential Energy

Kinetic Energy and Impact Force

Kinetic energy (KE) is the energy of an object in motion, given by the formula KE = 0.5mv², where m is mass and v is velocity. When the weight falls, it converts its potential energy into kinetic energy just before impact. The average force exerted on the pipe can be determined by analyzing the change in momentum during the impact and the distance over which the pipe is driven into the ground.
Recommended video:
Guided course
06:07
Intro to Rotational Kinetic Energy

Newton's Second Law of Motion

Newton's Second Law states that the force acting on an object is equal to the mass of that object multiplied by its acceleration (F = ma). This principle is crucial for calculating the average force exerted by the weight on the pipe. By determining the deceleration of the weight as it comes to a stop upon impacting the pipe, one can apply this law to find the average force exerted during the impact.
Recommended video:
Guided course
06:54
Intro to Forces & Newton's Second Law
Related Practice
Textbook Question
T ─ (1500 kg) (9.8 m/s²) = (1500 kg) (1.0 m/s²) P = T (2.0 m/s) (c) Finish the solution of the problem.
257
views
Textbook Question
The three ropes shown in the bird's-eye view of FIGURE EX9.18 are used to drag a crate 3.0 m across the floor. How much work is done by each of the three forces?
960
views
Textbook Question
The gravitational attraction between two objects with masses mᴀ and mᴃ, separated by distance 𝓍, is F = Gmᴀmᴃ/𝓍², where G is the gravitational constant. (b) If one mass is much greater than the other, the larger mass stays essentially at rest while the smaller mass moves toward it. Suppose a 1.5 x 10¹³ kg comet is passing the orbit of Mars, heading straight for the sun at a speed of 3.5 x 10⁴ m/s. What will its speed be when it crosses the orbit of Mercury? Astronomical data are given in the tables at the back of the book, and G = 6.67 x 10 ¯¹¹ Nm²/kg² ..
469
views
Textbook Question
A cable with 20.0 N of tension pulls straight up on a 1.50 kg block that is initially at rest. What is the block's speed after being lifted 2.00 m? Solve this problem using work and energy.
1299
views
1
comments
Textbook Question
CALC An object moving in the xy-plane is subjected to the force F(arrow on top) =(2xy î+x² ĵ) N, where x and y are in m. a. The particle moves from the origin to the point with coordinates (a, b) by moving first along the x -axis to (a, 0) , then parallel to the y -axis. How much work does the force do?
663
views
Textbook Question
In a hydroelectric dam, water falls 25 m and then spins a turbine to generate electricity. (a) What is (delta)Ug of 1.0 kg of water?
645
views