Now that we know how to name double bonds, there's an extra complication that we have to consider, which is that double bonds, because of the lack of free rotation, are going to be able to arrange themselves in different ways. So now we have to take into account not only the fact that there's a double bond and it has priority, but we're also going to have to take into account the arrangement of that double bond. So let's go ahead and get started. So I'm sure you've heard of the words cis and trans before. Cis and trans are names given to particular arrangements of double bonds or of rings. So, basically, any time that you have no free rotation, you're going to have the possibility for cis and trans. For example, a double bond, if two groups are oriented in the same position, remember that a double bond is pretty like has a lot of regions of overlap, so it can't twist out of shape. So that means the double bond is stuck there. In the same way, a ring has the same problem where if I, for example, have a ring that looks like this and then I have a group facing up and I also have another group facing up. Notice that this is like a 3D structure. Let's say this is one atom and another atom. See how they're both facing the same way? I can't actually rotate this one to the down position without breaking the ring because that ring, in order to move one down, would have to snap. So cis and trans are the words that we use for these arrangements that are stuck together. And, like I said, these isomers exist because free rotation around pi bonds is impossible. So, basically, the way that this works is that when two groups happen to be on the same side of the fence, okay, we're going to I'm going to talk about that in a second. When they're on the same side, that's going to be cis. When they're on different sides of the fence, that's going to be trans. So, what kind of mysterious fence am I talking about? Well, let's say we have a double bond. The way that I like to split it up is I like to draw a dotted line right through the middle of the double bond. That double bond is my fence. And then what I say is how are these groups related to each other on that double bond? So for example, if I wanted to compare and are they on the same side of the fence or different sides? Well, they're both on the same side. They're both on the top side, so the relationship between would be cis. What about the relationship between and What would that relationship be? Well, those are on different sides, so that one would be trans. Got that so far? How about the relationship between a and b? How about if I were to say what kind of relationship is that? A and b actually don't have a cis and trans relationship. The reason is because they're on the same carbon. Cis and trans only applies to atoms on other carbons, not on ones that are on your own carbon. So a and b would actually get a completely different type of name that we're not going to discuss here, but it wouldn't have to do with cis and trans. So cis and trans only has to do with the way that one atom to another relates to. Here I've got two different versions of 2-butene. When I say that, you shouldn't be shocked. You should know what I'm talking about because that means that's a butane with a double bond in the 2 position. Easy. But these are both not both the same molecule. In fact, they're going to have different physical properties. They're going to behave differently and stuff like that. So what would be the names that we would give to these to show that they're distinctly different? The names that we would give would be, well, I would draw my fence, and I would say okay, are these on the same side of the fence or different? Same. This one would be cis-2-butene. And then this one would be trans-2-butene. And these are, later on we're going to talk about them. There's something called stereo isomers which means that they actually are connected the same way but they're shaped differently. But for right now just know that these are molecules that are locked in their position and they can't move.
- 1. A Review of General Chemistry5h 9m
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- 6. Thermodynamics and Kinetics1h 22m
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- 11. Radical Reactions1h 58m
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- Thiol Reactions6m
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- 13. Alcohols and Carbonyl Compounds2h 17m
- 14. Synthetic Techniques1h 26m
- 15. Analytical Techniques:IR, NMR, Mass Spect6h 50m
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- Infrared Spectroscopy Table31m
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- 16. Conjugated Systems6h 13m
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- Diels-Alder Reaction9m
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- Molecular Orbital Theory9m
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- HOMO LUMO4m
- Orbital Diagram:3-atoms- Allylic Ions13m
- Orbital Diagram:4-atoms- 1,3-butadiene11m
- Orbital Diagram:5-atoms- Allylic Ions10m
- Orbital Diagram:6-atoms- 1,3,5-hexatriene13m
- Orbital Diagram:Excited States4m
- Pericyclic Reaction10m
- Thermal Cycloaddition Reactions26m
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- Thermal Electrocyclic Reactions14m
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- Cumulative Electrocyclic Problems25m
- Sigmatropic Rearrangement17m
- Cope Rearrangement9m
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- 17. Ultraviolet Spectroscopy51m
- 18. Aromaticity2h 31m
- 19. Reactions of Aromatics: EAS and Beyond5h 1m
- Electrophilic Aromatic Substitution9m
- Benzene Reactions11m
- EAS:Halogenation Mechanism6m
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- EAS:Any Carbocation Mechanism7m
- Electron Withdrawing Groups22m
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- Reactions at Benzylic Positions31m
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- EAS:Sequence Groups4m
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- Diazo Replacement Reactions6m
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- Nucleophilic Aromatic Substitution28m
- Benzyne16m
- 20. Phenols55m
- 21. Aldehydes and Ketones: Nucleophilic Addition4h 56m
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- Oxidizing and Reducing Agents9m
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- DIBAL5m
- Alkyne Hydration9m
- Nucleophilic Addition8m
- Cyanohydrin11m
- Organometallics on Ketones19m
- Overview of Nucleophilic Addition of Solvents13m
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- Hemiacetal9m
- Acetal12m
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- Thioacetal6m
- Imine vs Enamine15m
- Addition of Amine Derivatives5m
- Wolff Kishner Reduction7m
- Baeyer-Villiger Oxidation39m
- Acid Chloride to Ketone7m
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- Wittig Reaction18m
- Ketone and Aldehyde Synthesis Reactions14m
- 22. Carboxylic Acid Derivatives: NAS2h 51m
- Carboxylic Acid Derivatives7m
- Naming Carboxylic Acids9m
- Diacid Nomenclature6m
- Naming Esters5m
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- Acid Chloride Nomenclature5m
- Naming Anhydrides7m
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- Nucleophilic Acyl Substitution18m
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- Transesterification5m
- Lactones, Lactams and Cyclization Reactions10m
- Carboxylation5m
- Decarboxylation Mechanism14m
- Review of Nitriles46m
- 23. The Chemistry of Thioesters, Phophate Ester and Phosphate Anhydrides1h 10m
- 24. Enolate Chemistry: Reactions at the Alpha-Carbon1h 53m
- Tautomerization9m
- Tautomers of Dicarbonyl Compounds6m
- Enolate4m
- Acid-Catalyzed Alpha-Halogentation4m
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- Haloform Reaction8m
- Hell-Volhard-Zelinski Reaction3m
- Overview of Alpha-Alkylations and Acylations5m
- Enolate Alkylation and Acylation12m
- Enamine Alkylation and Acylation16m
- Beta-Dicarbonyl Synthesis Pathway7m
- Acetoacetic Ester Synthesis13m
- Malonic Ester Synthesis15m
- 25. Condensation Chemistry2h 9m
- 26. Amines1h 43m
- 27. Heterocycles2h 0m
- Nomenclature of Heterocycles15m
- Acid-Base Properties of Nitrogen Heterocycles10m
- Reactions of Pyrrole, Furan, and Thiophene13m
- Directing Effects in Substituted Pyrroles, Furans, and Thiophenes16m
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- 28. Carbohydrates5h 53m
- Monosaccharide20m
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- Glycoside6m
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- 29. Amino Acids3h 20m
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- L and D Amino Acids14m
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- Synthesis of Amino Acids: Acetamidomalonic Ester Synthesis16m
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- Reactions of Amino Acids: Esterification7m
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- Reactions of Amino Acids: Hydrogenolysis6m
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- 32. Lipids 2h 50m
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- 35. Transition Metals5h 33m
- Electron Configuration of Elements45m
- Coordination Complexes20m
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- Cross-Coupling General Reactions40m
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- Fukuyama Coupling Reaction15m
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- Negishi Coupling Reaction16m
- Buchwald-Hartwig Amination Reaction19m
- Eglinton Reaction17m
Cis vs Trans - Online Tutor, Practice Problems & Exam Prep
![](/channels/images/AIStars.png)
Understanding cis and trans isomerism is crucial for studying alkenes and cyclic compounds. Cis refers to groups on the same side of a double bond, while trans indicates groups on opposite sides. For multi-substituted alkenes, the E and Z naming system is used, where E denotes trans and Z denotes cis configurations based on the highest priority groups. This distinction is essential for predicting physical properties and reactivity in organic compounds, as these geometric isomers can exhibit different behaviors due to their spatial arrangements.
Since double bonds and rings can’t rotate, we need different names for the different arrangements they can create.Â
How to name different types of double bonds or rings
Video transcript
![Content](https://cdn.clutchprep.com/guide_visuals/inline_images/wRHR5iVTGOSaABHzN0Vi_24.png)
Two groups coming off the same carbon never have a cis/trans relationship. In case you are wondering, they are called geminal (you don’t need to know this yet.)
E/Z Nomenclature
The cis/trans nomenclature system is awesome, but it breaks down with multisubstituted alkenes.
Why we need to use the E/Z naming system
Video transcript
Now I want to talk about another naming system called E and Z. Okay? I call this the easy naming system and it's actually really easy. It's related to cis and trans. The only thing is that you use the E and Z naming system when you have multi-substituted alkenes. Okay. So I know you can barely see that, multi-substituted. Even you can see it and it still doesn't make a whole lot of sense. My handwriting is terrible. Okay. So multi-substituted alkenes. So let me give you an example. Let's go down to this example here, assign cis and trans to the following alkenes. I don't need names. I don't need full names. I just want to know if it's cis or trans. So let's start off with this first one. Would that one be cis or trans? The answer is that this would be trans. Okay? Because if I drew my fence along here, what you would see is that one group is on one side and one group is on the other. Does that make sense? Cool. How about 2? What would that be? 2 would be cis because both groups are on the same side. Okay? Now lastly, what about 3? What would you say about 3? Okay. So 3 is actually a trick question. There is no cis and trans. Why? Because I have 3 different groups. I have one here. I have one here, so that could be trans. But then I also have this one over here messing things up. Did I tell you how to figure out cis and trans when you have 3 things? No. So basically, the E and Z naming system is going to allow us to give unique names to tri- and tetra-substituted alkenes. What that means is that cis and trans only works if you have 2 substituents. But if you have more than 2, cis and trans breaks down like in example 3. Example 3, there's no way to use cis and trans there. So I have to use E and Z instead.
So the E/Z naming system allows us to name tri- and tetra- substituted alkenes.
The difference between E and Z
What does E and Z stand for?
Video transcript
When I'm using e and z, all I do is this. I'm going to choose the highest priority groups on both corners of the double bond. Okay? What does high priority mean? It means highest atomic mass. So I'm going to try to pick the side of the double bond. I'm going to try to pick on each side of the double bond the atom that has the highest atomic mass. That one's going to get my priority and then I'm going to figure out how those two high priority groups are related to each other. If they're related to each other trans, then we're going to assign the letter e. If they're related to each other as cis, then we're going to assign the letter z. So basically z is just a fancy way of saying cis with three or more substituents. E is a fancy way of saying trans with three or more substituents.
Using the periodic table to assign priorities, trans = E, and cis = Z.
Assigning E/Z
Video transcript
So I'm going to go through the first one by myself. What I mean by myself is with you guys, just guiding you through it. And then we'll see. Okay. So first of all, let's look at f. When I say that I have to identify the highest priority groups on both corners, what is a corner? I'm just talking about this being one corner and this being another. Okay. So let's look at the green one first. Is there a side of this double bond that is going to have the higher priority? Is there one of those substituents that's going to have a higher priority? And the answer is yes. Fluorine is going to have a higher priority over this group here. Why? Because even though this group down here looks bigger, the Fluorine has a higher atomic mass right away. So what that means is Fluorine beats carbon. Fluorine is further down the periodic table than carbon is, so this is going to be my high priority up here. Oops. Whatever. This is to be my high priority up here. Now let's move to red. So for red, is there a way to assign which one is higher priority? And actually, these are both exactly the same. They're both CH3. So this is an example where I actually have 4 different substituents, but since I have 2 of the same substituent on a corner, I can't assign cis and trans or e and z. Why? Because there's no way to distinguish these from each other. They're both the same thing. So actually, this one is going to be not available. I can't assign cis and trans unless there's different things on both sides. Okay? So what I'm trying to say is that there's no way for me to know if this is cis and trans because this CH3 is always going to be cis to the f and trans to the ethyl. This CH3 is always going to be cis to the ethyl and trans to the f, so it doesn't really matter. This one does not get a designation.
![Content](https://cdn.clutchprep.com/guide_visuals/inline_images/uTLQmuDQQTqp4GLg1WbO_25.png)
Assigning E/Z
Video transcript
Hey everyone. Now that we've done example a, let's take a look at example b. So here when we're looking at this alkene, the first thing we should do is find our corner carbons. Remember our corner carbons are just our alkene carbons. We're going to make this one our blue corner carbon and this one our black corner carbon. The next thing we're going to do is let's look at the blue one. What are the 2 groups that are attached to it? If we take a look we know there is a carbon here that's invisible and carbon has to make 4 bonds, so there is a hydrogen that's also present. If we look at carbon and hydrogen, which has higher priority? Carbon would have higher priority, so we're going to highlight that. Now let's take a look at our black corner carbon. Here, what 2 groups is it attached to? Well, it's attached to an oxygen here and a carbon here. Of these 2, which has higher priority? Oxygen would have higher priority. So now that we determined the 2 higher priority groups, let's draw our fence. And we see that our 2 higher priority groups are on the same side. Now remember, if we're dealing with a tri-substituted or tetra-substituted alkene, then we use the e or z designation. Since this is tri-substituted, we're going to use e or z. And they're on the same side, so that would be cis, and cis is related to z. So this is a z alkene. Now, echoing back to my French roots, a way that I remember what z means is z is the same side. Okay? So that's a way that I tend to try to remember what is a z alkene, how it's related to cis. Remember, if you were a z alkene, the opposite of that would be an e alkene. Alright. So just keep this in mind when taking a look at any of these types of alkene structures. So determine if they do in fact have an e or z designation.
![Content](https://cdn.clutchprep.com/guide_visuals/inline_images/Lsuyz7SVCuKXhZDFdYAh_26.png)
Great! Now let's combine this with what we've learned about functional groups (alkyl halides and alcohols) to name some more complex molecules.
Determine the IUPAC name of the following molecule
![Content](https://cdn.clutchprep.com/guide_visuals/inline_images/NanYFHBlQcKngXJaYdeo_27.png)
This was a great example of how the root chain must always have the functional group within it, even if it is shorter!
Determine the IUPAC name of the following molecule
![Content](https://cdn.clutchprep.com/guide_visuals/inline_images/7PKkFRqjSAygBkAehzYT_28.png)
Hope you don’t hate me for throwing two alcohols in there! This is great practice though.
Do you want more practice?
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- Identify the following alkenes as E or Z, if appropriate. (b)
- Identify the following alkenes as E or Z, if appropriate. (a)
- Given the name, draw the structure of the following alkenes.(b) ((Z)-1-cyclohexyl-2-methylhept-2-ene
- Draw the cis and trans isomers for the following: a. 1-bromo-4-chlorocyclohexane
- Disregarding stereoisomers, draw the structures of all alkenes with molecular formula C5H10. Which ones can ex...
- α -Farnesene is a dodecatetraene found in the waxy coating of apple skins. What is its systematic name? Includ...
- Draw skeletal structures for each pair of isomers in Problem 7b. <IMAGE>
- Why does cis-2-butene have a higher boiling point than trans-2-butene?
- Imines can exist as stereoisomers. The isomers are named using the E,Z system of nomenclature (Section 4.2 ). ...
- Draw and name all stereoisomers of 3-chlorohepta-2,4-dienea. using the cis-trans nomenclature.
- Which of the following cycloalkanes are capable of geometric (cis-trans) isomerism? Draw the cis and trans iso...
- Which of the following cycloalkanes are capable of geometric (cis-trans) isomerism? Draw the cis and trans iso...
- Draw a structure for each compound (includes old and new names).d. 1,3-cyclohexadienee. cycloocta-1,4-dienef. ...
- Determine which compounds show cis-trans isomerism.Draw and label the isomers, using both the cis-trans and E-...
- Which of the following cycloalkanes are capable of geometric (cis-trans) isomerism? Draw the cis and trans iso...
- Draw the molecular orbital picture of trans-but-2-ene.
- Draw skeletal structures for the compounds in Problem 3, including any cis–trans isomers.
- Draw skeletal structures for the compounds in Problem 3, including any cis–trans isomers.
- a. Draw the condensed structures and give the systematic names for all the alkenes with molecular formula C6H1...
- b. For those compounds that can exist as cis and trans isomers, draw and label the isomers. 1. CH3CH=CHCH2CH2...
- Draw the cis and trans isomers for the following: b. 1-ethyl-3-methylcyclobutane
- b. For those compounds that can exist as cis and trans isomers, draw and label the isomers. 2. CH3CH=CHCH3 4....
- Draw the structures and give the common and systematic names for the seven alkynes with molecular formula C6H1...
- 1. Draw the structure of cis-CH3CH=CHCH2CH3 showing the pi bond with its proper geometry. 2. Draw the trans i...
- Which of the following structures represent the same compound? Which ones represent different compounds?c. <...
- Name the following: a. b.
- Draw a structure for each compound (includes old and new names).g. vinylcyclopropaneh. (Z)-2-bromo-2-pentene
- Draw a structure for each compound (includes old and new names).i. (3Z,6E)-1,3,6-octatriene
- Draw the structure that corresponds to the name provided. (d) (2R,4Z)-5-bromopent-4-ene-1,2-diol
- Draw the structure that corresponds to the name provided. (b) (2R,3R,4S)-heptane-2,3,4-triol
- Provide the IUPAC name for the following molecules. (a)
- Draw the structure that corresponds to the name provided. (a) (1R,5S)-5-methylcyclohex-3-enol
- Name the following:a. <IMAGE>b. <IMAGE>
- For each of the following compounds, draw the possible geometric isomers and name each isomer: a. 2-methyl-2,4...
- For each of the following compounds, draw the possible geometric isomers and name each isomer: b. 1,5-heptadie...