Hey guys. So now we're going to talk about another way to represent organic structures and that's called the condensed structure. The condensed method is a common way to describe the connectivity. Connectivity, how a molecule is connected. So my speculation is that the logic behind this is that professors and chemists wanted a way to represent these molecules using only a text editor. Back in the day, there weren't these fancy drawing programs. In fact, all they had were typewriters. Right? And they wanted some way to be able to notate what a molecule looked like without having to draw fancy structures. Alright? And that's where they came upon the condensed structure. Now one thing that's important for this class is that you're going to have to really learn how to interconvert between bond line and condensed very quickly. The reason is because your professor, just to trick you, will use both structures interchangeably. One question might be in bond line, another question might be in condensed. And typically, just from my years of tutoring experience, I know that students really don't like to think in condensed structure because it's kind of tricky. So what I'm going to do today is I'm going to really show you, okay, how to interpret it. So let's go ahead and look at there are two different types. Let's start off with the full condensed structure. The full condensed structure is literally only text. And as you can see, we're taking a bond line structure and we're going to represent it in just only one line of text. Now, a lot of this is straightforward, meaning that you can see that this first CH3 here is represented by that CH3 there. Okay? So then you would think, oh, this isn't so bad. The confusing part is that parentheses can be used to represent different things depending on the subscript in front of them. So let's go ahead and look at that. The first interesting parenthesis that you should know is this one that I've indicated in blue, which is a CH2+ subscript. Okay? So notice that I have CH2(3). What that means is that I have a repeating unit that's going to happen over and over and over again. So when I have CH2 with a 3, that doesn't mean I have three CH2s sticking out of one place. What it means is I have three CH2's attached in order, like in a line. Does that make sense so far? The reason that saves us a lot of time is because some of these molecules can get really, really long. Imagine having a molecule that's a 100 carbons long. Do you want to write a 100 CH2's? No. It's way easier just to put CH2 in parentheses with a 100 underneath it. And that means I'm going to repeat this unit 100 times. Cool so far? Awesome. So let's keep going. Then we have this red one. The red one is parentheses alone. If you have parentheses alone, that indicates that you have a branch coming off of the chain. Alright? Now what's going to be interesting here is that sometimes these parentheses are optional, meaning that your professor may not always be so nice as to put those parentheses there to say that there's a branch. Sometimes you're just going to have to know, alright, let's look at the logic here. I have a carbon right here and that carbon is attached to two other things. It's attached to one half of the chain on the left and one half of the chain on the right. Right? By the way, this carbon, let's go ahead and locate it. It's this one right here. Okay? So let's just make sure that we know what we're talking about. Okay? So that carbon has a part of the chain on the left and a part of the chain on the right. Okay? But it also has supposed to have two other things coming off of it because remember carbon wants to have four bonds. Right? So what are those two other things? Well, there's an H, that means that I have one H sticking off there. Okay? And I also have an OH. Now notice that in this case I was nice and I put it in parentheses. What that meant was that it's very easy to say, oh, the OH is the thing that's coming off here. Done. I have my four bonds. Perfect. But sometimes you might see it as just CHOH. And then what you would need to know is that, okay, one of them, the H is going in one direction, the OH is going in the other, but you know that both of them are attached to that carbon because remember that carbon needs 4 bonds. That's kind of the way that we think about it. You always think in terms of how can I make carbon have 4 bonds? Finally, as you can see, there's one more type of parenthesis. Sorry about getting a little sidetracked, but I want you guys to see an example of that. And then the last one is that if I have something else that's in parentheses other than CH2 and has a number in front of it. So in this case, I'm giving you CH3 with a 2 in the magenta brackets. Okay? And what that means is that these things are not attached in a line, they're both attached to the same carbon. Okay? So basically the only time that I have things in a line repeating is if it's CH2. That would mean that it would be linear. So go ahead and write that down. Linear meaning that it's all in one line. But if I have 2 things that are not CH3 or 3, like here, these would indicate branching. Okay? Because of the fact that both of these CH3s must be coming off of 1 carbon and what that would be is that they would be attached to this one right here. Okay? Now let's look at the logic with this one. So let's look at this carbon. Where is that carbon? That carbon is right here. Okay? So that carbon needs to have four things attached to it. Right? Well, first of all, it has the whole left part of the chain. Easy. And then it has, let's look at it. Let's see what's after the carbon. After the carbon, I have an H and I have a CH2, I mean, and I have a CH carbon, I have an H and I have a CH2, I mean, and I have a CH3 and then I have another CH3 because it says 2. Those are the three other things that are attached to that carbon. So this would be bond 2, bond 3 and bond attached to that carbon. So this would be bond 2, bond 3 and bond 4. And if we were to go ahead and draw that, you would see that I have an H here and then I have CH3 here and then I have CH3 here. Do you get that? At the end of the day, the carbon still has 4 bonds, so it's fine. But if you ever draw a structure, if you ever translate a structure that does not give carbon 4 bonds, then you know you made a mistake.
- 1. A Review of General Chemistry5h 9m
- Summary23m
- Intro to Organic Chemistry5m
- Atomic Structure16m
- Wave Function9m
- Molecular Orbitals17m
- Sigma and Pi Bonds9m
- Octet Rule12m
- Bonding Preferences12m
- Formal Charges6m
- Skeletal Structure14m
- Lewis Structure20m
- Condensed Structural Formula15m
- Degrees of Unsaturation15m
- Constitutional Isomers14m
- Resonance Structures46m
- Hybridization28m
- Molecular Geometry16m
- Electronegativity22m
- 2. Molecular Representations1h 14m
- 3. Acids and Bases2h 46m
- 4. Alkanes and Cycloalkanes4h 19m
- IUPAC Naming29m
- Alkyl Groups13m
- Naming Cycloalkanes10m
- Naming Bicyclic Compounds10m
- Naming Alkyl Halides7m
- Naming Alkenes3m
- Naming Alcohols8m
- Naming Amines15m
- Cis vs Trans21m
- Conformational Isomers13m
- Newman Projections14m
- Drawing Newman Projections16m
- Barrier To Rotation7m
- Ring Strain8m
- Axial vs Equatorial7m
- Cis vs Trans Conformations4m
- Equatorial Preference14m
- Chair Flip9m
- Calculating Energy Difference Between Chair Conformations17m
- A-Values17m
- Decalin7m
- 5. Chirality3h 39m
- Constitutional Isomers vs. Stereoisomers9m
- Chirality12m
- Test 1:Plane of Symmetry7m
- Test 2:Stereocenter Test17m
- R and S Configuration43m
- Enantiomers vs. Diastereomers13m
- Atropisomers9m
- Meso Compound12m
- Test 3:Disubstituted Cycloalkanes13m
- What is the Relationship Between Isomers?16m
- Fischer Projection10m
- R and S of Fischer Projections7m
- Optical Activity5m
- Enantiomeric Excess20m
- Calculations with Enantiomeric Percentages11m
- Non-Carbon Chiral Centers8m
- 6. Thermodynamics and Kinetics1h 22m
- 7. Substitution Reactions1h 48m
- 8. Elimination Reactions2h 30m
- 9. Alkenes and Alkynes2h 9m
- 10. Addition Reactions3h 18m
- Addition Reaction6m
- Markovnikov5m
- Hydrohalogenation6m
- Acid-Catalyzed Hydration17m
- Oxymercuration15m
- Hydroboration26m
- Hydrogenation6m
- Halogenation6m
- Halohydrin12m
- Carbene12m
- Epoxidation8m
- Epoxide Reactions9m
- Dihydroxylation8m
- Ozonolysis7m
- Ozonolysis Full Mechanism24m
- Oxidative Cleavage3m
- Alkyne Oxidative Cleavage6m
- Alkyne Hydrohalogenation3m
- Alkyne Halogenation2m
- Alkyne Hydration6m
- Alkyne Hydroboration2m
- 11. Radical Reactions1h 58m
- 12. Alcohols, Ethers, Epoxides and Thiols2h 42m
- Alcohol Nomenclature4m
- Naming Ethers6m
- Naming Epoxides18m
- Naming Thiols11m
- Alcohol Synthesis7m
- Leaving Group Conversions - Using HX11m
- Leaving Group Conversions - SOCl2 and PBr313m
- Leaving Group Conversions - Sulfonyl Chlorides7m
- Leaving Group Conversions Summary4m
- Williamson Ether Synthesis3m
- Making Ethers - Alkoxymercuration4m
- Making Ethers - Alcohol Condensation4m
- Making Ethers - Acid-Catalyzed Alkoxylation4m
- Making Ethers - Cumulative Practice10m
- Ether Cleavage8m
- Alcohol Protecting Groups3m
- t-Butyl Ether Protecting Groups5m
- Silyl Ether Protecting Groups10m
- Sharpless Epoxidation9m
- Thiol Reactions6m
- Sulfide Oxidation4m
- 13. Alcohols and Carbonyl Compounds2h 17m
- 14. Synthetic Techniques1h 26m
- 15. Analytical Techniques:IR, NMR, Mass Spect6h 50m
- Purpose of Analytical Techniques5m
- Infrared Spectroscopy16m
- Infrared Spectroscopy Table31m
- IR Spect:Drawing Spectra40m
- IR Spect:Extra Practice26m
- NMR Spectroscopy10m
- 1H NMR:Number of Signals26m
- 1H NMR:Q-Test26m
- 1H NMR:E/Z Diastereoisomerism8m
- H NMR Table21m
- 1H NMR:Spin-Splitting (N + 1) Rule17m
- 1H NMR:Spin-Splitting Simple Tree Diagrams11m
- 1H NMR:Spin-Splitting Complex Tree Diagrams8m
- 1H NMR:Spin-Splitting Patterns8m
- NMR Integration18m
- NMR Practice14m
- Carbon NMR4m
- Structure Determination without Mass Spect47m
- Mass Spectrometry12m
- Mass Spect:Fragmentation28m
- Mass Spect:Isotopes27m
- 16. Conjugated Systems6h 13m
- Conjugation Chemistry13m
- Stability of Conjugated Intermediates4m
- Allylic Halogenation12m
- Reactions at the Allylic Position39m
- Conjugated Hydrohalogenation (1,2 vs 1,4 addition)26m
- Diels-Alder Reaction9m
- Diels-Alder Forming Bridged Products11m
- Diels-Alder Retrosynthesis8m
- Molecular Orbital Theory9m
- Drawing Atomic Orbitals6m
- Drawing Molecular Orbitals17m
- HOMO LUMO4m
- Orbital Diagram:3-atoms- Allylic Ions13m
- Orbital Diagram:4-atoms- 1,3-butadiene11m
- Orbital Diagram:5-atoms- Allylic Ions10m
- Orbital Diagram:6-atoms- 1,3,5-hexatriene13m
- Orbital Diagram:Excited States4m
- Pericyclic Reaction10m
- Thermal Cycloaddition Reactions26m
- Photochemical Cycloaddition Reactions26m
- Thermal Electrocyclic Reactions14m
- Photochemical Electrocyclic Reactions10m
- Cumulative Electrocyclic Problems25m
- Sigmatropic Rearrangement17m
- Cope Rearrangement9m
- Claisen Rearrangement15m
- 17. Ultraviolet Spectroscopy51m
- 18. Aromaticity2h 31m
- 19. Reactions of Aromatics: EAS and Beyond5h 1m
- Electrophilic Aromatic Substitution9m
- Benzene Reactions11m
- EAS:Halogenation Mechanism6m
- EAS:Nitration Mechanism9m
- EAS:Friedel-Crafts Alkylation Mechanism6m
- EAS:Friedel-Crafts Acylation Mechanism5m
- EAS:Any Carbocation Mechanism7m
- Electron Withdrawing Groups22m
- EAS:Ortho vs. Para Positions4m
- Acylation of Aniline9m
- Limitations of Friedel-Crafts Alkyation19m
- Advantages of Friedel-Crafts Acylation6m
- Blocking Groups - Sulfonic Acid12m
- EAS:Synergistic and Competitive Groups13m
- Side-Chain Halogenation6m
- Side-Chain Oxidation4m
- Reactions at Benzylic Positions31m
- Birch Reduction10m
- EAS:Sequence Groups4m
- EAS:Retrosynthesis29m
- Diazo Replacement Reactions6m
- Diazo Sequence Groups5m
- Diazo Retrosynthesis13m
- Nucleophilic Aromatic Substitution28m
- Benzyne16m
- 20. Phenols55m
- 21. Aldehydes and Ketones: Nucleophilic Addition4h 56m
- Naming Aldehydes8m
- Naming Ketones7m
- Oxidizing and Reducing Agents9m
- Oxidation of Alcohols28m
- Ozonolysis7m
- DIBAL5m
- Alkyne Hydration9m
- Nucleophilic Addition8m
- Cyanohydrin11m
- Organometallics on Ketones19m
- Overview of Nucleophilic Addition of Solvents13m
- Hydrates6m
- Hemiacetal9m
- Acetal12m
- Acetal Protecting Group16m
- Thioacetal6m
- Imine vs Enamine15m
- Addition of Amine Derivatives5m
- Wolff Kishner Reduction7m
- Baeyer-Villiger Oxidation39m
- Acid Chloride to Ketone7m
- Nitrile to Ketone9m
- Wittig Reaction18m
- Ketone and Aldehyde Synthesis Reactions14m
- 22. Carboxylic Acid Derivatives: NAS2h 51m
- Carboxylic Acid Derivatives7m
- Naming Carboxylic Acids9m
- Diacid Nomenclature6m
- Naming Esters5m
- Naming Nitriles3m
- Acid Chloride Nomenclature5m
- Naming Anhydrides7m
- Naming Amides5m
- Nucleophilic Acyl Substitution18m
- Carboxylic Acid to Acid Chloride6m
- Fischer Esterification5m
- Acid-Catalyzed Ester Hydrolysis4m
- Saponification3m
- Transesterification5m
- Lactones, Lactams and Cyclization Reactions10m
- Carboxylation5m
- Decarboxylation Mechanism14m
- Review of Nitriles46m
- 23. The Chemistry of Thioesters, Phophate Ester and Phosphate Anhydrides1h 10m
- 24. Enolate Chemistry: Reactions at the Alpha-Carbon1h 53m
- Tautomerization9m
- Tautomers of Dicarbonyl Compounds6m
- Enolate4m
- Acid-Catalyzed Alpha-Halogentation4m
- Base-Catalyzed Alpha-Halogentation3m
- Haloform Reaction8m
- Hell-Volhard-Zelinski Reaction3m
- Overview of Alpha-Alkylations and Acylations5m
- Enolate Alkylation and Acylation12m
- Enamine Alkylation and Acylation16m
- Beta-Dicarbonyl Synthesis Pathway7m
- Acetoacetic Ester Synthesis13m
- Malonic Ester Synthesis15m
- 25. Condensation Chemistry2h 9m
- 26. Amines1h 43m
- 27. Heterocycles2h 0m
- Nomenclature of Heterocycles15m
- Acid-Base Properties of Nitrogen Heterocycles10m
- Reactions of Pyrrole, Furan, and Thiophene13m
- Directing Effects in Substituted Pyrroles, Furans, and Thiophenes16m
- Addition Reactions of Furan8m
- EAS Reactions of Pyridine17m
- SNAr Reactions of Pyridine18m
- Side-Chain Reactions of Substituted Pyridines20m
- 28. Carbohydrates5h 53m
- Monosaccharide20m
- Monosaccharides - D and L Isomerism9m
- Monosaccharides - Drawing Fischer Projections18m
- Monosaccharides - Common Structures6m
- Monosaccharides - Forming Cyclic Hemiacetals12m
- Monosaccharides - Cyclization18m
- Monosaccharides - Haworth Projections13m
- Mutarotation11m
- Epimerization9m
- Monosaccharides - Aldose-Ketose Rearrangement8m
- Monosaccharides - Alkylation10m
- Monosaccharides - Acylation7m
- Glycoside6m
- Monosaccharides - N-Glycosides18m
- Monosaccharides - Reduction (Alditols)12m
- Monosaccharides - Weak Oxidation (Aldonic Acid)7m
- Reducing Sugars23m
- Monosaccharides - Strong Oxidation (Aldaric Acid)11m
- Monosaccharides - Oxidative Cleavage27m
- Monosaccharides - Osazones10m
- Monosaccharides - Kiliani-Fischer23m
- Monosaccharides - Wohl Degradation12m
- Monosaccharides - Ruff Degradation12m
- Disaccharide30m
- Polysaccharide11m
- 29. Amino Acids3h 20m
- Proteins and Amino Acids19m
- L and D Amino Acids14m
- Polar Amino Acids14m
- Amino Acid Chart18m
- Acid-Base Properties of Amino Acids33m
- Isoelectric Point14m
- Amino Acid Synthesis: HVZ Method12m
- Synthesis of Amino Acids: Acetamidomalonic Ester Synthesis16m
- Synthesis of Amino Acids: N-Phthalimidomalonic Ester Synthesis13m
- Synthesis of Amino Acids: Strecker Synthesis13m
- Reactions of Amino Acids: Esterification7m
- Reactions of Amino Acids: Acylation3m
- Reactions of Amino Acids: Hydrogenolysis6m
- Reactions of Amino Acids: Nihydrin Test11m
- 32. Lipids 2h 50m
- 34. Nucleic Acids1h 32m
- 35. Transition Metals5h 33m
- Electron Configuration of Elements45m
- Coordination Complexes20m
- Ligands24m
- Electron Counting10m
- The 18 and 16 Electron Rule13m
- Cross-Coupling General Reactions40m
- Heck Reaction40m
- Stille Reaction13m
- Suzuki Reaction25m
- Sonogashira Coupling Reaction17m
- Fukuyama Coupling Reaction15m
- Kumada Coupling Reaction13m
- Negishi Coupling Reaction16m
- Buchwald-Hartwig Amination Reaction19m
- Eglinton Reaction17m
Condensed Structural Formula - Online Tutor, Practice Problems & Exam Prep
![](/channels/images/AIStars.png)
The condensed structure is a textual representation of organic molecules, allowing chemists to convey connectivity without drawings. It uses parentheses to indicate repeating units, such as CH2(n), and branches, where a carbon atom must have four bonds. Understanding these representations is crucial for interconverting between bond line and condensed structures, as both formats may appear in assessments. Mastery of this concept aids in visualizing molecular architecture and ensures accurate interpretation of complex organic compounds.
What if you want to describe a molecule, but you have nothing but a keyboard? (No fancy pictures or drawings). This is was actually a big dilemma in the chemistry world, which is why we now have condensed structure.
Condensed Rules
How to interpret condensed structures.
Video transcript
![Content](https://cdn.clutchprep.com/guide_visuals/inline_images/SkT4XkxxRTSnV8KcJZUx_162.png)
The condensed structure shows us the connectivity of the molecule. The use of parentheses is important:
- Parentheses with no subscripts: Branch on the chain.
- Parenthesis with subscripts: Multiple branches on a chain.
- CH2 within parentheses + subscripts: Repeating CH2 units within a chain.
Condensed Mixed Structures
How to draw condensed mixed structures.
Video transcript
Alright. So now let's look at one that's a little bit easier, and that's the condensed mix structure. The condensed mix structure is one in which I have a ring. So I'm just going to put here "rings". Okay? The reason is because rings are very, very difficult. If you think about it, rings would be very difficult to draw in a text because a ring could be a certain shape, it's 2-dimensional, and most text editors don't give you the ability to draw up and across. It's only to go across. Think that you're on a typewriter. Would you be able to type a ring? No. So what you do with the condensed mixed structure is that the ring is the only thing that stays this bond line, and then everything else that's branching off of it goes to condensed. So, as you can see, what I do is I take this thing, convert it over here, and now all of the branches coming off of the ring become a condensed formula. Does that make sense so far? Cool.
I also wanted to talk about a few other things right here. Notice that with this, let's start off with this one because it's kind of easy. Okay? What I have is think about it. I have parenthesis that has, does it have CH2 in parenthesis? No. It's something other than CH2. Right? It's actually CH3. So that must mean what? Does it mean that all the CH3's are in a line? No. That would only be if it was CH2. What it means is that all 3 CH3's are coming off of the same carbon. Does that make sense? And that's what we see right here. I have carbon and then CH3 CH3 CH3. Does that make sense? Cool. I hope so.
Now let's go to one that's a little bit trickier. That is this one over on the left-hand side. So now what is this weird line that I drew? Like where did that come from? This line is a pretend line. Okay? So don't pay too much attention to it. All I'm trying to do is separate the right side from the left side to show you how we draw it differently. Okay? Now because condensed structure has to do with connection, it has to do with what is connected to what, when you're on the left-hand side of a mixed structure, you always have to draw in reverse. You have put the letters backwards. Okay? The reason is because I have to show exactly what order they're connected in. So let's look at this. This right here is an O attached to a CH3. Would you agree with that? Cool. But if I just write if I, instead of writing this, let's say that I wrote O CH3 like that. Would that be correct? That would actually be incorrect. So go ahead and put an X on that. K? That would be wrong. The reason is because it looks like the O is attached to one of the H's. Right? That doesn't make a lot of sense. So the way we need to show this is that the O is actually connected to the carbon first, and the carbon is connected to 3 H's. Right? So then the way that we draw it is O, C, and then H3 after that. Does that make sense? This only applies when you're on the left side. Because if you're on the right side, then it just makes sense the way it naturally is. You would just write it out according to the connectivity. The left side is the part that gets a little bit tricky.
Now, some of you guys might be asking this question, Johnny, but what if it's the top or at the bottom? Because that's not really how about if it's in between? So how about if I had a line right here and I wanted to put text there? Well, if it's right in the middle, then obviously go to the right because I can just do CH3O or whatever. Or I could do, in this case, it would be O CH3 if it had been there. Okay? So obviously what I'm trying to say is that you would only go to the left, you would only reverse it if you absolutely have to because it's on the left-hand side. Does that make sense? But if it's at the top or the bottom, just go to the right like normal because there's plenty of room to draw it. Okay?
So, let's go to the last example, which is this one down here that has a double bond to carbon and to oxygen. That's this thing right there. Okay? This is a situation where if you have a double bond, many times your professor is going to put an equal sign there. An equal sign represents a double bond, which is pretty easy. If it was a triple bond, then they would put one of the equal signs that has 3 bars. Bars. K? But sometimes your professors will be really tricky, and they will just write this like C=OCH3 and they will skip the equal sign. That's tricky. Right? How are you supposed to know that that is a double bond without being told that it's a double bond? Can you guys think about it? Is there any way to know? The answer is it goes back to carbon having 4 bonds. Okay? If this is a carbon and an oxygen, and if that carbon needs 4 bonds, then what that means is that this carbon must be attached to that oxygen with a double bond. The reason is because I have a bond on the left, I have a bond on the right, and then I must have 2 bonds that are missing. Those 2 bonds that are missing are the ones that are attached to the O that makes it a double bond right there. Does that kind of make sense? Now, like I was saying, most professors are going to be nice, and they're going to give you that double bond. But I'm just trying to show you just in case your professor decides to be a tool and not put that in there so that you guys will know that you can actually calculate it based on carbon having 4 bonds. Okay? So I'm going to give you plenty of practice. Don't worry.
![Content](https://cdn.clutchprep.com/guide_visuals/inline_images/pU6ONWURmh7dctG695rg_163.png)
This is similar to normal condensed structure, except there is a bondline ringed component. Always draw your condensed letters in terms of connectivity!
- If to the right of the ring:Draw branch normally.
- If to the left of the ring:Draw branch in reverse.
Convert the condensed structure into a bondline structure
Remember, the exact direction of your zig-zag pattern doesn’t matter as long as everything is connected correctly. Single bonds can rotate freely, so let’s not spend lots of time worrying about the exact angles you drew.
Do you want more practice?
More setsYour Organic Chemistry tutors
- Draw line-angle structures for the compounds (a) through (h). c. CH3CH2COCN d. CH2CHCHO
- Draw line-angle structures for the compounds (a) through (h). c. CH3CH2COCN d. CH2CHCHO
- Draw the condensed structure of a compound that contains only carbon and hydrogen atoms and that has a. three...
- Draw the lone-pair electrons that are not shown in the following condensed structures: a. CH3CH2NH2 b. CH3NH...
- Convert the following condensed structures into skeletal structures:
- Convert the following condensed structures into skeletal structures: CH3CH2CH2CH2CH2CH2OH
- Draw a skeletal structure for each of the compounds. c. CH3COOH
- Convert the following condensed structures into skeletal structures: <IMAGE>
- Convert the following condensed structures into skeletal structures: CH3CH2NHCH2CH2CH3
- Draw condensed structures for the compounds represented by the following models (black=C, gray=H, red=O, blue=...
- Draw condensed structures for the compounds represented by the following models (black=C, gray=H, red=O, blue=...
- Draw a complete structural formula and a condensed structural formula fora. three compounds of formula C3H8O
- (•) Represent each of the following condensed structural formulas using a line-angle drawing.(d) <IMAGE>
- (•) Represent each of the following condensed structural formulas using a line-angle drawing.(e) <IMAGE>
- Convert the following structural formulas to line-angle drawings (c) CH₃CH₂NHCH₂CH₂OH
- For each of the following molecules, draw a 3-D representation.(c) CHBr₃
- For each of the following molecules, draw a 3-D representation.(d) CHClBrI
- (•) Represent each of the following condensed structural formulas using a line-angle drawing.(c) <IMAGE>
- Draw a skeletal structure for each of the compounds. a. CH3CHOb. CH3OCH3
- Draw line-angle structures for the compounds (a) through (h).g. (CH3CH2)2COh. (CH3)3COH
- Draw line-angle structures for the compounds (a) through (h).a. CH3(CH2)3CH(CH3)2 b. (CH3)2CHCH2Cl
- Draw a line-angle formula for each compound. a. CH3COCH2CHCHCOOHb. NCCH2COCH2CHO
- Draw a line-angle formula for each compound. c. H2CHCH(OH)CH2CO2H d. CH2CHC(CH3)CHCOOCH3
- Draw a Lewis structure for each compound. Include all nonbonding pairs of electrons. a. CH3COCH2CHCHCOOH b. N...
- Draw a Lewis Structure for each species. e. CH3CHO f. CH3S(O)CH3 g. H2SO4 h. CH3NCO
- Draw a Lewis Structure for each species. a. N2H4 b. N2H2 c. (CH3)2NH2Cl d. CH3CN
- A. Draw a Lewis structure for each of the following: 4. CH3CONH2
- For each of the given species: a. Draw its Lewis structure. b. Describe the orbitals used by each carbon atom...
- Draw a Lewis structure for each of the following: b. HNO2
- Draw a Lewis structure for each of the following:b. CH3OCH3
- Draw a Lewis structure for each of the following:c. (CH3)2CHCH(CH3)CH2C(CH3)3
- Change the following condensed structures to Kekulé structures:a. CH3NH(CH2)2CH3b. (CH3)2CHCl
- Draw a Lewis Structure for each species. i. CH3OSO2OCH3j. CH3C(NH)CH3k. (CH3)3CNO
- Draw complete Lewis structures for the following condensed structural formulas.CH2CHCHO(CH3)3CCOCHCH2