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Ch. 6 - Genetic Analysis and Mapping in Bacteria and Bacteriophages

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Klug 12th Edition

Ch. 6 - Genetic Analysis and Mapping in Bacteria and Bacteriophages

Problem 21

Chapter 6, Problem 21

During the analysis of seven rII mutations in phage T4, mutants 1, 2, and 6 were in cistron A, while mutants 3, 4, and 5 were in cistron B. Of these, mutant 4 was a deletion overlapping mutant 5. The remainder were point mutations. Nothing was known about mutant 7. Predict the results of complementation (+ or -) between 1 and 2; 1 and 3; 2 and 4; and 4 and 5.

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Hello, everyone. Today we have a question asking which of the following is the end result of Bender's work, Benzer isolated many independence of our two mutants by performing recombination all studies to create the genetic map of this locus. And what this done was result in the production of the detailed map of the R two locus. So our answer is D Thank you for watching. Bye.

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Related Practice

Textbook Question

If further testing of the mutations in Problem 18 yielded the following results, what would you conclude about mutant 5? Mutants Results 2, 5 - 3, 5 - 4, 5 -

Textbook Question

Using mutants 2 and 3 from Problem 19, following mixed infection on E. coli B, progeny viruses were plated in a series of dilutions on both E. coli B and K12 with the following results. What is the recombination frequency between the two mutants? Strain Plated Dilution Plaques E. coli B 10⁻⁵ 2 E. coli K12 10⁻¹ 5

Textbook Question

Using mutants 2 and 3 from Problem 19, following mixed infection on E. coli B, progeny viruses were plated in a series of dilutions on both E. coli B and K12 with the following results. Another mutation, 6, was tested in relation to mutations 1 through 5 from Problems 18–20. In initial testing, mutant 6 complemented mutants 2 and 3. In recombination testing with 1, 4, and 5, mutant 6 yielded recombinants with 1 and 5, but not with 4. What can you conclude about mutation 6?

Textbook Question

In studies of recombination between mutants 1 and 2 from Problem 21, the results shown in the following table were obtained. Strain Dilution Plaques Phenotypes E. coli B 10⁻⁷ 4 r E. coli K12 10⁻² 8 + Calculate the recombination frequency.

Textbook Question

In studies of recombination between mutants 1 and 2 from Problem 21, the results shown in the following table were obtained. Strain Dilution Plaques Phenotypes E. coli B 10⁻⁷ 4 r E. coli K12 10⁻² 8 + When mutant 6 was tested for recombination with mutant 1, the data were the same as those shown above for strain B, but not for K12. The researcher lost the K12 data, but remembered that recombination was ten times more frequent than when mutants 1 and 2 were tested. What were the lost values (dilution and plaque numbers)?

Textbook Question

In studies of recombination between mutants 1 and 2 from Problem 21, the results shown in the following table were obtained. Strain Dilution Plaques Phenotypes E. coli B 10⁻⁷ 4 r E. coli K12 10⁻² 8 + Mutant 7 (Problem 21) failed to complement any of the other mutants (1–6). Define the nature of mutant 7.