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Ch. 5 - Chromosome Mapping in Eukaryotes
Chapter 5, Problem 31

Drosophila melanogaster has one pair of sex chromosomes (XX or XY) and three pairs of autosomes, referred to as chromosomes II, III, and IV. A genetics student discovered a male fly with very short (sh) legs. Using this male, the student was able to establish a pure breeding stock of this mutant and found that it was recessive. She then incorporated the mutant into a stock containing the recessive gene black (b, body color located on chromosome II) and the recessive gene pink (p, eye color located on chromosome III). A female from the homozygous black, pink, short stock was then mated to a wild-type male. The F₁ males of this cross were all wild type and were then backcrossed to the homozygous b, p, sh females. The F₂ results appeared as shown in the following table. No other phenotypes were observed. Wild Pink* Black, Black, Pink, Short* Short Females 63 58 55 69 Males 59 65 51 60 *Other trait or traits are wild type. The student repeated the experiment, making the reciprocal cross, F₁ females backcrossed to homozygous b, p, sh males. She observed that 85 percent of the offspring fell into the given classes, but that 15 percent of the offspring were equally divided among b + p, b + +, + sh p, and + sh + phenotypic males and females. How can these results be explained, and what information can be derived from the data?

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Sex-linked Inheritance

In Drosophila melanogaster, sex-linked inheritance refers to traits that are determined by genes located on the sex chromosomes (X or Y). Since males have one X and one Y chromosome (XY), any recessive traits on the X chromosome will be expressed in males, as they lack a second X chromosome to mask the effect. Understanding this concept is crucial for interpreting the inheritance patterns observed in the crosses described in the question.
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Recessive and Dominant Alleles

Alleles can be classified as dominant or recessive based on their expression in the phenotype. A recessive allele, such as the short legs (sh) in this case, will only manifest in the phenotype when present in a homozygous state (two copies). In contrast, dominant alleles will express their traits even in a heterozygous state. This concept is essential for analyzing the results of the genetic crosses and understanding the ratios of phenotypes in the offspring.
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Backcrossing and F2 Generation Analysis

Backcrossing involves mating a hybrid organism with one of its parents or an individual genetically similar to its parents to determine the genotype of the offspring. The F2 generation results from crossing F1 hybrids, and analyzing their phenotypic ratios can reveal information about the inheritance patterns of traits. In this scenario, the observed ratios and the presence of unexpected phenotypes in the offspring provide insights into gene linkage and potential recombination events.
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Related Practice
Textbook Question
A female of genotype a b c + + + produces 100 meiotic tetrads. Of these, 68 show no crossover events. Of the remaining 32, 20 show a crossover between a and b, 10 show a crossover between b and c, and 2 show a double crossover between a and b and between b and c. Of the 400 gametes produced, how many of each of the 8 different genotypes will be produced? Assuming the order a–b–c and the allele arrangement previously shown, what is the map distance between these loci?

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Textbook Question
In laboratory class, a genetics student was assigned to study an unknown mutation in Drosophila that had a whitish eye. He crossed females from his true-breeding mutant stock to wild-type (brick-red-eyed) males, recovering all wild-type F₁ flies. In the F₂ generation, the following offspring were recovered in the following proportions: wild type 5/8 bright red 1/8 brown eye 1/8 white eye 1/8 The student was stumped until the instructor suggested that perhaps the whitish eye in the original stock was the result of homozygosity for a mutation causing brown eyes and a mutation causing bright red eyes, illustrating gene interaction (see Chapter 4). After much thought, the student was able to analyze the data, explain the results, and learn several things about the location of the two genes relative to one another. One key to his understanding was that crossing over occurs in Drosophila females but not in males. Based on his analysis, what did the student learn about the two genes?
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Textbook Question
Drosophila melanogaster has one pair of sex chromosomes (XX or XY) and three pairs of autosomes, referred to as chromosomes II, III, and IV. A genetics student discovered a male fly with very short (sh) legs. Using this male, the student was able to establish a pure breeding stock of this mutant and found that it was recessive. She then incorporated the mutant into a stock containing the recessive gene black (b, body color located on chromosome II) and the recessive gene pink (p, eye color located on chromosome III). A female from the homozygous black, pink, short stock was then mated to a wild-type male. The F₁ males of this cross were all wild type and were then backcrossed to the homozygous b, p, sh females. The F₂ results appeared as shown in the following table. No other phenotypes were observed. Wild Pink* Black, Black, Pink, Short* Short Females 63 58 55 69 Males 59 65 51 60 *Other trait or traits are wild type. Based on these results, the student was able to assign short to a linkage group (a chromosome). Which one was it? Include your step-by-step reasoning.
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Textbook Question
In Drosophila, a female fly is heterozygous for three mutations, Bar eyes (B), miniature wings (m), and ebony body (e). Note that Bar is a dominant mutation. The fly is crossed to a male with normal eyes, miniature wings, and ebony body. The results of the cross are as follows. 111 miniature 101 Bar, ebony 29 wild type 31 Bar, miniature, ebony 117 Bar 35 ebony 26 Bar, miniature 115 miniature, ebony Interpret the results of this cross. If you conclude that linkage is involved between any of the genes, determine the map distance(s) between them.
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Textbook Question
The gene controlling the Xg blood group alleles (Xg⁺ and Xg⁻) and the gene controlling a newly described form of inherited recessive muscle weakness called episodic muscle weakness (EMWX) (Ryan et al., 1999) are closely linked on the X chromosome in humans at position Xp22.3 (the tip of the short arm). A male with EMWX who is Xg⁻ marries a woman who is Xg⁺ and they have eight daughters and one son, all of whom are normal for muscle function, the male being Xg⁺ and all the daughters being heterozygous at both the EMWX and Xg loci. Following is a table that lists three of the daughters with the phenotypes of their husbands and children. For each of the offspring, indicate whether or not a crossover was required to produce the phenotypes that are given.
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Textbook Question
How would the results vary in cross (a) of Problem 32 if genes A and B were linked with no crossing over between them? How would the results of cross (a) vary if genes A and B were linked and 20 map units (mu) apart?
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