The gel presented here shows the pattern of bands of fragments produced with several restriction enzymes. The enzymes used are identified above the lanes of the gel, and six possible restriction maps are shown in the column to the right.
One of the six restriction maps shown is consistent with the pattern of bands shown in the gel.
From your analysis of the pattern of bands on the gel, select the correct restriction map and explain your reasoning. <>.
Most of the techniques described in this chapter (blotting, cloning, PCR, etc.) are dependent on hybridization (annealing) between different populations of nucleic acids. Length of the strands, temperature, and percentage of GC nucleotides weigh considerably on hybridization. Two other components commonly used in hybridization protocols are monovalent ions and formamide. A formula that takes monovalent Na⁺ ions ((M[Na⁺]) and formamide concentrations into consideration to compute a Tₘ (temperature of melting) is as follows:
Tₘ=81.5+16.6(log M[Na+])+0.41(%GC)−0.72(%formamide)
For the following concentrations of Na⁺ and formamide, calculate the Tₘ. Assume 45% GC content.
[Na⁺] % Formamide
0.825 20
0.825 40
0.165 20
0.165 40
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Key Concepts
Hybridization
Melting Temperature (Tₘ)
Role of Monovalent Ions and Formamide
The gel presented here shows the pattern of bands of fragments produced with several restriction enzymes. The enzymes used are identified above the lanes of the gel, and six possible restriction maps are shown in the column to the right.
One of the six restriction maps shown is consistent with the pattern of bands shown in the gel.
The highlighted bands (magenta) in the gel hybridized with a probe for the gene pep during a Southern blot. Where in the gel is the pep gene located?
A widely used method for calculating the annealing temperature for a primer used in PCR is 5 degrees below the melting temperature, Tₘ(°C), which is computed by the equation 81.5+0.41×(%GC)−(675/N), where %GC is the percentage of GC nucleotides in the oligonucleotide and N is the length of the oligonucleotide. Notice from the formula that both the GC content and the length of the oligonucleotide are variables. Assuming you have the following oligonucleotide as a primer,
5′-TTGAAAATATTTCCCATTGCC-3′
compute the annealing temperature for PCR. What is the relationship between and %GC? Why? (Note: In reality, this computation provides only a starting point for empirical determination of the most useful annealing temperature.) <>
Most of the techniques described in this chapter (blotting, cloning, PCR, etc.) are dependent on hybridization (annealing) between different populations of nucleic acids. Length of the strands, temperature, and percentage of GC nucleotides weigh considerably on hybridization. Two other components commonly used in hybridization protocols are monovalent ions and formamide. A formula that takes monovalent Na⁺ ions ((M[Na⁺]) and formamide concentrations into consideration to compute a Tₘ (temperature of melting) is as follows:
Tₘ=81.5+16.6(log M[Na+])+0.41(%GC)−0.72(%formamide)
Given that formamide competes for hydrogen bond locations on nucleic acid bases and monovalent cations are attracted to the negative charges on nucleic acids, explain why the Tₘ varies as described in part (a).
In humans, congenital heart disease is a common birth defect that affects approximately 1 out of 125 live births. Using reverse transcription PCR (RT-PCR) Samir Zaidi and colleagues [(2013) Nature 498:220.223] determined that approximately 10 percent of the cases resulted from point mutations, often involving histone function. To capture products of gene expression in developing hearts, they used oligo(dT) in their reverse transcription protocol.
How would such a high %T in a primer influence annealing temperature?
In humans, congenital heart disease is a common birth defect that affects approximately 1 out of 125 live births. Using reverse transcription PCR (RT-PCR) Samir Zaidi and colleagues [(2013) Nature 498:220.223] determined that approximately 10 percent of the cases resulted from point mutations, often involving histone function. To capture products of gene expression in developing hearts, they used oligo(dT) in their reverse transcription protocol.
Compared with oligo(dT) primers, a pool of random sequence primers requires a trickier assessment of annealing temperature. Why?