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Ch. 15 - Gene Mutation, DNA Repair, and Transposition
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All textbooksKlug 12th EditionCh. 15 - Gene Mutation, DNA Repair, and TranspositionProblem 23

Chapter 15, Problem 23

In a bacterial culture in which all cells are unable to synthesize leucine (leu⁻), a potent mutagen is added, and the cells are allowed to undergo one round of replication. At that point, samples are taken, a series of dilutions are made, and the cells are plated on either minimal medium or minimal medium containing leucine. The first culture condition (minimal medium) allows the growth of only leu⁺ cells, while the second culture condition (minimal medium with leucine added) allows growth of all cells. The results of the experiment are as follows: Culture Condition Dilution Colonies Minimal medium 10⁻¹ 18 Minimal medium + leucine 10⁻⁷ 9 What is the rate of mutation at the locus associated with leucine biosynthesis?

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Everyone. Let's take a look at this question together if a bacteria has a 10 to the five bases per genome. What is the rate of mutations per genome replication? Considering that the bacteria of a mutation rate of 10 to the power of negative 10 mutations per base times replication. Well to solve this question we have to go ahead and do some math. So let's set up our equation to try to figure out what the correct answer is. So we know that we have 10 to the power of five bases per genome for that bacteria which we can see here and we're gonna go ahead and multiply it by the mutation rate of 10 to the power of negative 10 mutations divided by base times replication. So we go 10 to the power of negative 10 mutations over space times replication. And so we're looking at this 10 to the five times 10 to the power of negative 10. Which when we do the math we end up with 10 to the power of negative five and that is mutations over jean. Um application which is answer choice B. The correct answer because when we take that 10 to the five basis per genome from that bacteria and multiply it by the mutation rate of 10 to the power of negative 10 we end up with 10 to the power of negative five mutations per genome replication which is answer choice B. The correct answer. I hope you found this video to be helpful. Thank you and goodbye
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Textbook Question
Many of the gene products involved in DNA synthesis were initially defined by studying mutant E. coli strains that could not synthesize DNA. The dnaE gene encodes the α subunit of DNA polymerase III. What effect is expected from a mutation in this gene? How could the mutant strain be maintained?
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Many of the gene products involved in DNA synthesis were initially defined by studying mutant E. coli strains that could not synthesize DNA. The dnaQ gene encodes the ε subunit of DNA polymerase. What effect is expected from a mutation in this gene?
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A fellow student considers the issues in Problem 22 and argues that there is a more straightforward, nongenetic experiment that could differentiate between the two types of mutations. The experiment requires no fancy genetics and would allow you to easily assay the products of the other SOS genes. Propose such an experiment.
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