The A and B antigens in humans may be found in water-soluble form...

Question

The A and B antigens in humans may be found in water-soluble form in secretions, including saliva, of some individuals (Se/Se and Se/se) but not in others (se/se). The population thus contains 'secretors' and 'nonsecretors.'

How will the results of such matings change if both parents are heterozygous for the gene controlling the synthesis of the H substance (Hh)?

Accepted Answer

Hey everyone. Let's take a look at this question together. H Bombay blood group is a recessive phenotype and mutations in the foot one gene. Are the cause of this blood group as it controls the synthesis of H. Antigen on RBC surfaces determine the percentage of offspring with the H. Bombay blood group. When both the parents have a blood group O. And R. Hetero zegas. For the foot one gene. So to solve this question we have to go ahead and cross both parents and upon it square to see the percentage of offspring that have that H. Bombay blood group. So here we have both parents. And let's go ahead and do that cross to figure out what the percentage of the offspring will have that H. Bombay blood group. So here we have all of the genotype of the offspring from both parents. And we know that the H. Bombay blood group is a recessive phenotype. So the only group here that has that recessive phenotype is this one which makes this one the Bombay the load group. And so looking at the pundit square, we know that we only have that one group right here, which means that we have one out of four offspring have the Bombay blood group. So that would be a 25% chance which makes answer choice B. The correct answer. Because when we cry both of those parents that have the blood group O. And are hetero ziggy's for the foot one gene we end up with a 25% chance of the offspring having that Bombay blood group which makes be the correct answer. I hope you found this video to be helpful. Thank you and goodbye.

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