What is the molarity of ZnCl₂ that forms when 25.0 g of zinc completely reacts with CuCl₂ according to the following reaction? Assume a final volume of 275 mL. Zn(s) + CuCl₂(aq) → ZnCl₂(aq) + Cu(s)

Video transcript

Hello everyone. Today we have a phone problem. What is the molarity of zinc chloride that forms when 25 g of zinc completely reacts with copper chloride according to the following reaction, assume a final volume of 275 mL. So first, we want to start with our given which was 25 g of zinc. Let me want to do a couple of conversions. The first is we want to do a molar mass conversion, which if we look at the periodic table, we can state that one mole of zinc is equal or equivalent to 65.39 g of zinc. From there, we want to perform a multiple ratio to get from moles of zinc to moles of zinc chloride. And so if we look at our equation, we see that we used one mole of zinc to create or to produce one mole of zinc chloride. We then like in our unit. So far, we can cancel out grams of zinc and moles of zinc. So recall that molar mass is the grams over moles or moles over grams. So what we can do is we can multiply one final our molarity is what we need to solve for is going to be moles over liters. So we can multiply by our 275. But we can say that we have our 1/2 75 mL can be multiplied. Brother Rachel, that 1 mL is equal to 10 to the negative third liters. When those units cancel, we are left with 1.39 molar molars of zinc chloride. And with that, we're gonna conclude our answer c overall, I hope it helped. And until next time.