Write structural formulas for each of the possible isomers of n-pentyne that are formed by moving the position of the triple bond.

Video transcript

Hi everyone here, we have a question asking us to provide the structural formula for the isthmus of in hex sign that can be created by shifting the triple bonds position. So we have the prefix hex which means six and then we have a line which means it's an alkaline and that means it has a triple bond. So we're gonna start off with our six carbons one, two three for 5, 6. And now we're gonna add our triple bond. So we're gonna add that right here and then we're going to add hydrogen to fill all the carbons octet. It's so we'll have three hydrogen on our end carbon here and we'll have to hear the ones with the triple bond get none because they're octaves are already filled And again are in hydrogen gets three. So that is the first structuralism herb in hex sign. And to create our second summer, we're going to move the triple bond and we are going to move it here. So we'll have our six carbons still 12, 3456. But now our triple bond is going to be here and we're gonna fill it with hydrogen. And lastly we're going to move our triple bond to the end. If we moved over one more, it would be the same as our first I summer because when naming our molecules, we always have it. So the double bond is closest to the end. So this is the last way to make a new ice summer and we're gonna have our six carbons again but our triple bond is going to be here and we're going to fill up our hydrogen. And that is our last summer. So here are our three structural ice emerge that can be created by shifting the triple bonds position. Thank you for watching. Bye.