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Ch.12 - Liquids, Solids & Intermolecular Forces

Chapter 12, Problem 82

Argon has a normal boiling point of 87.2 K and a melting point (at 1 atm) of 84.1 K. Its critical temperature is 150.8 K and its critical pressure is 48.3 atm. It has a triple point at 83.7 K and 0.68 atm. Sketch the phase diagram for argon. Which has the greater density, solid argon or liquid argon?

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Hey everyone, we're told that krypton has, it's triple point at 100 and 15.775 kelvin and 73 point to kill a pascal's the normal at 101.325. Kill A pascal's melting. And boiling temperatures are 100 and 15.79 K. And 100 and 19.93 K. Its critical temperature and pressure. Our 209.41 K and 5500. Kill A pascal's. With these values, sketch the phase diagram for krypton and his solid krypton denser than liquid krypton. So first let's go ahead and write out our given values. So here I will separate our pressure and our temperature. So here I will separate our pressure. So here I will separate our pressure and our temperature. So for the first one we have our triple point For our triple point, we were told that we were at 115.775 Kelvin And our pressure is at 73 point to kill a pass. Scouts next looking at our normal melting. Next looking at our melting. Next looking at our melting temperature, We are at our normal pressure of 101.325. Kill a Pascal's And our temperature is at 115.79 Kelvin. Now let's go ahead and now let's go ahead and look at our boiling temperature 1st. Let's go ahead and write first. Let's go ahead and write out our given values. So I will go ahead and separate our pressure versus our temperature. So starting with our triple point We were told our pressure is at 73 point to kill a pascal's and our temperature is at 115.775 Kelvin. Next looking at our melting temperature, We were told that we were at our normal pressure of 101.325. Kill a Pascal's And our temperature is at 115.79 Kelvin. Now let's go ahead and look at her boiling for our boiling again. We were at our normal pressure of 101.3 25 Kill A pascal's and our temperature is at 100 and 19.93 kelvin. And lastly looking at our critical temperature and are critical pressure, We were told that our pressure is at 5500. Kill a Pascal's while our temperature is at 209.41 Kelvin. So now that we've written out our values, let's go ahead and sketch out our phase diagram. So here I'll pull up our phase diagram and first we had to label our axes with X. Being our temperature in kelvin and why being our pressure in kila pascal's Next, we have to locate the exact points. So here we have our melting point, our triple point our boiling point and our critical point which are all values that we labeled, which are all values that we which are all values that we had organized Next we have to draw next we have to draw the curved lines. Next we have to draw the curved lines passing through the marked points. So these points right here and from left to right we have to label our phases. So from the left we have our solid followed by our liquid and then lastly our gas. Now the low temperatures are most appropriate for the solid phase while the high temperatures are most suitable for the gas phase. Now to answer whether solid krypton is denser than liquid krypton, the answer would be that solid krypton is denser, then liquid krypton. And the reason why is because the slope of the solid liquid equilibrium is positive. So we can see that slope right here. So increasing the pressure of krypton in the liquid phase will give us that solid phase. And these are going to be our final answers. Now, I hope this made sense. And let us know if you have any questions