Name each alkyne. c.

Video transcript

Welcome back, everyone name the al kind given below. As the problem suggests, we are given an alky. And this is because our hydrocarbon contains a triple bond. And we have to recall that the first step in naming Alkins is to identify the parent, which is the longest continuous carbon chain. And now it is really important to understand that we're going to enumerate that parent in a way such that we minimize the lo of the triple bond. We immediately notice that if we start enumerating our longest continuous carbon chain from left to right, we will be able to get the lowest possible lon for the triple bond, which is one. And now we can go along our chain and get our 2nd, 3rd, 4th, 5th and 6th carbon. If we move up, that would be the same, right? Because carbon number four is bonded to the same to substituents. So our parent is hex sign, that's because six has a prefix of hex, right? And for an L kind, the suffix is YME. However, we want to modify it slightly and specify the position of the triple bond because it starts at carbon number one, we're going to turn it into one hex sign. And our next step is to identify the substituents. Specifically, we're going to consider branching. What we notice is that we have two substituents bonded to carbon. Number 41 of them is the simplest possible methyl substituent since we have one carbon, right, with three implicit hydrogens, and the next one is called an ethyl substituent since it is a she remembered LK group, so we can essentially say that carbon four contains a methyl substitute. So we're going to use four dash methyl and four dash sl we want to arrange our subscriptions alphabetically in the name. So we're going with for fl first because we're comparing E against M followed by four muscle. And now let's finish our name with the parent which is one heck sign. So the complete name of the given Alky would be four ethyl, four methyl, one hex sign. Thank you for watching.