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Ch.22 - Organic Chemistry

Chapter 22, Problem 57d

List the products of each alkene addition reaction. d.

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Welcome back everyone. What is the product formed in the following alkene reaction? As the problem suggests, the starting material is an alkene because it contains a double bond and it reacts with hydrochloric acid. We have to understand that this is a hydro halogen reaction because our acid contains hydrogen and chlorine. In these cases, whenever we are dealing with a similar reaction, we have to identify our more substituted carbon within the double bond and our less substituted carbon within the double bond, we can clearly see that one of them is more substituted and the other one is less substituted. Now, to determine the product, we have to recall that the less substituted carbon gets attached to hydrogen and the more substituted carbon gets attached to the halogen. In this case, chlorine. And we're also breaking the pi bond. So we can now draw the result on structure. We can just begin with the original structure and simply eliminate the pi bond from it. Now, what we're going to do is add that hydrogen, we have already done. So there is no necessity to show it there to implicit hydrogens. And now our final step is to add chlorine to the more substituted carbon. That's it. That's how we get our product and we have successfully obtained that product based on the menik of school. That's how we call it. Thank you for watching.