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Ch.21 - Radioactivity & Nuclear Chemistry

Chapter 21, Problem 31a

Write a nuclear equation for the indicated decay of each nuclide. a. U-234 (alpha)

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Hey everyone, we're asked to consider the isotope thorium 2 28. And to write the nuclear equation for the alpha decay of the mentioned isotope. Looking at thorium in our periodic table, we see that it has an atomic number of 90. And since we know this will undergo an alpha decay, we can simply identify the missing particle by taking the mass number of thorium, which is 2 28 and subtracting the four from our alpha particle, which will get us to a mass number of 2 taking our 90 from our thorium, which is its atomic number and subtracting R two from r alpha particle, we get to an atomic number of 88. This tells us our missing particle is going to be radium 2 24. So I hope this made sense. And let us know if you have any questions.