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Ch.21 - Radioactivity & Nuclear Chemistry

Chapter 21, Problem 90

The nuclide 6Li reacts with 2H to form two identical particles. Identify the particles.

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Hey everyone, we're told that two identical particles are created when the new glide nitrogen and hydrogen to interact. What are the particles first? Let's go ahead and write out what we know. We have nitrogen 14. And when we look at our periodic table, we know it has an atomic number of seven. And we have a hydrogen too. And we know that its atomic number is one. These are going to be equal to two identical particles. And we can label this as X. For now with an atomic mass and an atomic number First. Let's all for a we can add nitrogen atomic mass of and we add it with hydrogen atomic massive too. And this will be equivalent to to A Since we had two identical particles Solving for a. We get 16 equals to a and a is going to be eight next for our Z. Which is our atomic number. We're going to add nitrogen seven and hydrogen is one. This will get us to two Z. And solving for Z. We got or and looking at our periodic table, it looks like we're going to have brilliant um eight since brilliant has an atomic number of four. So, I hope this made sense. And let us know if you have any questions