A solution is 0.010 M in Ba²⁺ and 0.020 M in Ca²⁺. b. What is the remaining concentration of the cation that precipitates first, when the other cation begins to precipitate?

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Hello everyone today we are being asked to solve the following problem says potassium carbonate is used to precipitate the cat ions in a solution that contains 0.25 molar of manganese and 0.5 molar of zinc two plus when the two carry ons. Or when the second countdown starts to precipitate what would be the remaining concentration of the cattle that precipitates first? So the first thing we wanna do is they want to draw our potassium carbonate dissociating into the respective ions. So when it does that it's going to form two potassium plus a chris ions as well as one carbonate, a crease ion. And so therefore we can see that the concentration of potassium carbonate is equal to the concentration of carbonate. Next we need to draw our potassium carbonate reacting with manganese two plus and we're gonna draw reacting with zinc as well. So when we have this reaction we're gonna have manganese carbon eight plus two, potassium plus Aquarius ions. Now we're going to go ahead and form the solid version of manganese carbonate and that's what we're going to be working with for ice table. So we're going to take our solid manganese carbonate and we're going to associate that inter forming manganese two plus ions as well as one carbonate ion. And so now we can draw our ice table for this one, we're not worried about a solid. So we can leave the mega knees column empty but for regular Megane is the initial concentration is given by the question is 0.25. And for carbonate itself zero we're gonna add plus X. As the change since we don't know the concentrations that we're trying to find out and then he is going to be I plus C, however X is so small, it can be considered negligible. So we're just gonna have to have our 00.0 to five in there for manganese and X. For carbonate, we know that the K. S. P. For this reaction is going to be 2.24 times 10 to the -11. And so we're going to go ahead and equal that to our K. Sp expression which is that the concentration of manganese two plus times the concentration of carbonate to minus. Of course when we simplify this even more, we get 2.24 times 10 to the negative 11. We're gonna go ahead and equal that to the concentration of manganese which was given to us as 110.25, but the concentration Of carbon is unknown. So we're just gonna mark that with X, solving for X, which is also the concentration for our carbonate is going to be equal to 8.96 times 10 to the -11. Next we must do the same thing we did earlier, but with zinc. So we must react our potassium carbonate with zinc two plus Aquarius. And when we do that, we form zinc carbonate in the solid form as well as to potassium plus acquis ions, we take the solid and we were going to dissociate it. So we're going to take zinc carbonate solid. And we're going to associate that form zinc two plus ions as well as one carbonate to minus ion. Setting up our ice table that we have here. We're not worried about the solid zinc carbonate since it is a solid. But for zinc the initial concentration is .050. And for carbonate it's going to be zero. The change is going to be plus X. For both compounds. Since we're only we're only dealing with one each and then he is going to be our I plus C. And since X is so small we can consider it negligible. So it's just gonna be .05. But for carbonate it's going to be X. We know the K. S. P. For our zinc carbonate is going to be equal to 1.46 times 10 to the negative 10. Setting up our K. Sp expression. Again it's going to be the concentration of zinc two plus times the concentration of C. 032 minus. Simplifying this even further, we get 1.46 times 10 to the negative 10 is equal to the concentration of zinc two plus which is 20.50 times the concentration of carbonate. However, it's X. So we don't know it yet solving for X. Or the concentration of carbonate. We are going to arrive at an answer of 2.92 times to the -9 moller. We can see that the concentration for our zinc is going to be much less than that of or is going to be greater than that of our concentration for carbonate when it reacts with manganese. And so we can conclude that manganese two Plus precipitates 1st. So it's going to precipitate first. Now we must find the remaining concentration and to do that, we must say we must use our K. Sp expression as before with our mega knees. Two plus since that is the compounded interest times are concentration of carbonate, We're gonna see the K. S. P. is going to be equal to 2.24 times 10 to the -11. And we're going to equal that too. The concentration of manganese, which we don't have yet. We're gonna multiply that by our K. By our concentration of carbonate that we found in the previous calculation, which is 2.92 times 10 to the negative nine. And we arrive at the answer that the concentration of manganese is going to be equal to 7.69 times 10 to the negative three molar. Overall, I hope this helped. And until next time

A solution is 0.010 M in Ba²⁺ and 0.020 M in Ca²⁺. b. What is the remaining concentration of the cation that precipitates first, when the other cation begins to precipitate?

Verified Solution

Key Concepts

Solubility Product Constant (Ksp)

Precipitation Reaction

Common Ion Effect

A solution is 0.010 M in Ba2+ and 0.020 M in Ca2+. b. What is the remaining concentration of the cation that precipitates first, when the other cation begins to precipitate?

Verified Solution

Key Concepts

Solubility Product Constant (Ksp)

Precipitation Reaction

Common Ion Effect

A solution is 0.010 M in Ba²⁺ and 0.020 M in Ca²⁺. b. What is the remaining concentration of the cation that precipitates first, when the other cation begins to precipitate?