Consider the reaction: N (g) + 3H (g) ⇌ 2NH (g) Complete the table. Assume that all concentrations are equilib- rium concentrations in M. T (K) [n2] [H2] [nH3] Kc 500 0.115 0.105 0.439 575 0.110 ________ 0.128 775 0.120 0.140 ________ ________ 9.6 0.0584

Video transcript

Hello everyone today we are being given a problem and asked to calculate for K C for the reaction. So we have 30 degrees Celsius, a reaction A plus two moles of B gives us two moles of C is found to have equilibrium concentrations of varying amounts for a B and C. So the first thing I wanna do is write our equilibrium expression and for equilibrium expressions we are going to only include gasses and solutions. So in the numerator we're going to put in brackets our products and since we have a two as a coefficient, that coefficient will become the exponent for that compound in our denominator, we're going to put our reactant so we're going to put A and be in their own respective brackets. Now notice how B has a coefficient of two. So we're going to Put a two as the exponent for B. And so now we're simply going to plug in the values for our concentrations, the concentration for C is 2.25. We're going to square that For a it is 0. And for B it is 1.12. And we're going to square that. After solving for the math, we get a final KC value of 4.862. I hope this helped. And until next time