Consider the elements: Na, Mg, Al, Si, P. a. Which element has the highest second ionization energy?

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Hey everyone here, it says which of the following elements has the lowest value of second ionization energy. Now here they're saying lowest value. That means it requires the least amount of energy to do. So this question is really saying which one of these options is it easiest for us to remove the second electron. Here we have aluminum, sodium, boron, barium, and carbon. Now, if we think about it, elements either gain or lose electrons to become more like the noble gasses, the one that requires the lowest amount of energy to remove the second electron is the one that wants to lose that second electron out of these options, which one wants to lose that second electron. And the answer would be option four. Barium Barium is in group two a. It wants to get a charge of two plus doing that helps it to become just like the noble gas before it. Okay, so because of this, the least amount of energy will be required to remove its second electron. So option four. Barium would be our final answer.

Consider the elements: Na, Mg, Al, Si, P. a. Which element has the highest second ionization energy?

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