Open Question
Convert between energy units. a. 231 cal to kJ b. 132×104 kJ to kcal d. 2.88×104 J to Cal
Ch.6 - Thermochemistry
Chapter 6, Problem 36a,b
A particular frost-free refrigerator uses about 745 kWh of electrical energy per year. Express this amount of energy in each unit. a. J b. kJ
Verified step by step guidance1
Step 1: Understand the relationship between kilowatt-hours (kWh) and joules (J). 1 kWh is equivalent to 3.6 million joules (3.6 x 10^6 J).
Step 2: To convert the energy usage from kWh to joules, multiply the given energy in kWh by the conversion factor (3.6 x 10^6 J/kWh).
Step 3: Calculate the energy in joules using the formula: Energy (J) = Energy (kWh) x 3.6 x 10^6 J/kWh.
Step 4: To convert joules to kilojoules (kJ), use the conversion factor where 1 kJ = 1000 J.
Step 5: Calculate the energy in kilojoules by dividing the energy in joules by 1000.
Related Practice
Open Question
A 2.74-g sample of a substance suspected of being pure gold is warmed to 72.1 °C and submerged into 15.2 g of water initially at 24.7 °C. The final temperature of the mixture is 26.3 °C. What is the heat capacity of the unknown substance? Could the substance be pure gold?
Open Question
Convert between energy units. a. 534 kWh to J b. 215 kJ to Cal c. 567 Cal to J d. 2.85 × 103 J to cal
Textbook Question
Convert between energy units. c. 4.99 × 103 kJ to kWh
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