Complete and balance each gas-evolution equation. b. NH 4 I(aq) + NaOH(aq) →

Hi everyone. So here we have a reaction between chris and money and bromine and aqueous rubidium hydroxide is going to produce a gas mask to write a balanced equation for the gas evolution reaction. So let's first look at each reacting. We have the money in bromine And it's going to dissociate into NH four plus. Must be art minus. And then we have rubidium hydroxide which is also a quiz. And it's going to associate into our beat plus plus O. H minus. So this is a double displacement reaction. We have two compounds reacting so we can switch the ions and form new products. We're gonna NH four plus plus O. H minus. And this is going to give us NH four O H NH four O. H. He's gonna decompose to give us ammonia Which is NH three yes plus water which is H +20. Like what? And then we're gonna have our B plus, that would be our minus. And this is Aquarius. So for the reaction we're gonna have money and bromine which is a quiz. That's rubidium hydroxide which is also a quiz and it's going to get ammonia plus water class rubidium bromine since we have the same number of each element on both sides. This equation is balanced. Thanks for watching my video and I hope it was helpful

Ch.4 - Chemical Quantities & Aqueous Reactions

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Tro 4th Edition

Ch.4 - Chemical Quantities & Aqueous Reactions

Problem 91b

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Chapter 4, Problem 91b

Complete and balance each gas-evolution equation. b. NH₄I(aq) + NaOH(aq) →

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Identify the reactants: Ammonium iodide \((\text{NH}_4\text{I})\) and sodium hydroxide \((\text{NaOH})\).

Recognize that \(\text{NH}_4^+\) from \(\text{NH}_4\text{I}\) will react with \(\text{OH}^-\) from \(\text{NaOH}\) to form ammonia gas \((\text{NH}_3)\) and water \((\text{H}_2\text{O})\).

Write the unbalanced equation: \(\text{NH}_4\text{I} + \text{NaOH} \rightarrow \text{NH}_3 + \text{H}_2\text{O} + \text{NaI}\).

Balance the equation by ensuring the number of each type of atom is the same on both sides of the equation.

Verify that the equation is balanced by checking that the total charge and the number of each type of atom are equal on both sides.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Gas-Evolution Reactions

Gas-evolution reactions are chemical reactions that produce a gas as one of the products. These reactions often involve the combination of an acid and a base, leading to the formation of a gas, water, and a salt. Understanding the types of gases produced, such as carbon dioxide or ammonia, is crucial for predicting the outcome of the reaction.

Balancing Chemical Equations

Balancing chemical equations is the process of ensuring that the number of atoms for each element is the same on both sides of the equation. This is based on the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction. Proper balancing is essential for accurately representing the stoichiometry of the reaction.

Acid-Base Neutralization

Acid-base neutralization is a chemical reaction where an acid reacts with a base to produce water and a salt. In the context of the given reaction, ammonium iodide (NH4I) acts as a weak acid, while sodium hydroxide (NaOH) is a strong base. The products of this reaction include water and sodium iodide (NaI), along with the potential release of ammonia gas.

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Textbook Question

A 25.00-mL sample of an unknown HClO₄ solution requires titration with 22.62 mL of 0.2000 M NaOH to reach the equivalence point. What is the concentration of the unknown HClO₄ solution? The neutralization reaction is HClO₄(aq) + NaOH(aq) → H₂O(l) + NaClO₄(aq)

A 30.00-mL sample of an unknown H₃PO₄ solution is titrated with a 0.100 M NaOH solution. The equivalence point is reached when 26.38 mL of NaOH solution is added. What is the concentration of the unknown H₃PO₄ solution? The neutralization reaction is H₃PO₄(aq) + 3 NaOH(aq) → 3 H₂O(l) + Na₃PO₄(aq)