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Ch.2 - Atoms & Elements
Chapter 2, Problem 107b

Carbon-12 contains six protons and six neutrons. The radius of the nucleus is approximately 2.7 fm (femtometers) and the radius of the atom is approximately 70 pm (picometers). What percentage of the carbon atom's volume is occupied by the nucleus? (Assume two significant figures.)

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Calculate the volume of the nucleus using the formula for the volume of a sphere: $V = \frac{4}{3} \pi r^3$, where $r$ is the radius of the nucleus in femtometers.
Convert the radius of the atom from picometers to femtometers to ensure both radii are in the same units. (1 pm = 1000 fm)
Calculate the volume of the atom using the same formula for the volume of a sphere: $V = \frac{4}{3} \pi r^3$, where $r$ is the radius of the atom in femtometers.
Determine the percentage of the atom's volume occupied by the nucleus by dividing the volume of the nucleus by the volume of the atom and multiplying by 100%.
Express the final answer with two significant figures as required by the problem.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Atomic Structure

The atomic structure consists of a nucleus, which contains protons and neutrons, and electrons that orbit around the nucleus. In the case of Carbon-12, the nucleus has six protons and six neutrons, while the electrons occupy a much larger volume outside the nucleus. Understanding this structure is essential for calculating the relative sizes and volumes of the nucleus and the atom.
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Atom Structure

Volume Calculation

To determine the volume of the nucleus and the atom, we use the formula for the volume of a sphere, V = (4/3)πr³, where r is the radius. The nucleus of Carbon-12 has a radius of approximately 2.7 femtometers, while the atom has a radius of about 70 picometers. Accurate volume calculations are crucial for finding the percentage of the atom's volume occupied by the nucleus.
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Percentage Calculation

Calculating the percentage of the atom's volume occupied by the nucleus involves dividing the volume of the nucleus by the volume of the atom and then multiplying by 100. This concept is fundamental in comparing the relative sizes of different components within an atom, highlighting how much space the nucleus occupies in relation to the entire atom.
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Related Practice
Open Question

Fill in the blanks to complete the table. Symbol Z A Number of p Number of e− Number of n Charge ______ 8 ______ ______ ______ 8 2- Ca2 + 20 ______ ______ ______ 20 ______ Mg2 + ______ 25 ______ ______ 13 2+ N3 - ______ 14 ______ 10 ______ ______

Textbook Question

Neutron stars are composed of solid nuclear matter, primarily neutrons. Assume the radius of a neutron is approximately 1.0×10–13 cm. Calculate the density of a neutron. [Hint: For a sphere V = (4/3)πr3.] Assuming that a neutron star has the same density as a neutron, calculate the mass (in kg) of a small piece of a neutron star the size of a spherical pebble with a radius of 0.10 mm.

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Textbook Question

Carbon-12 contains six protons and six neutrons. The radius of the nucleus is approximately 2.7 fm (femtometers) and the radius of the atom is approximately 70 pm (picometers). Calculate the volume of the nucleus and the volume of the atom.

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Textbook Question

A penny has a thickness of approximately 1.0 mm. If you stacked Avogadro's number of pennies one on top of the other on Earth's surface, how far would the stack extend (in km)? [For comparison, the sun is about 150 million km from Earth and the nearest star (Proxima Centauri) is about 40 trillion km from Earth.]

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Textbook Question

Consider the stack of pennies in the previous problem. How much money (in dollars) would this represent? If this money were equally distributed among the world's population of 7.0 billion people, how much would each person receive? Would each person be a millionaire? A billionaire? A trillionaire?

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Textbook Question

The mass of an average blueberry is 0.75 g and the mass of an automobile is 2.0×103 kg. Find the number of automobiles whose total mass is the same as 1.0 mol of blueberries.

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