Fill in the missing particles in each nuclear equation. d. ⁷⁵₃₅Br → ____ + ⁰₊₁e

Video transcript

Welcome back everyone in this example. We need to give the bounced nuclear equation for the positron emission of roaming 75. So let's go ahead and begin with our target new glide which is given in the prompt as bromine, 75, being its mass number which we recall is represented in the left hand exponents. When we refer to our periodic tables to find bro mean we see that it corresponds to atomic number 35 found in the D. Block of our periodic table. And we know that this is going to be producing a positron particle, which we should recall is represented by the symbol E. And has a atomic number of plus one and a mass number of zero. And we need to figure out the unknown product new glide produced from our positron emission of Rome in 75. So we are going to identify this unknown product X. Where we need to figure out its mass number a and its atomic number Z. So we're going to have to set up an expression with our knowns to sulfur are unknowns A and C. Beginning with finding a. Let's plug in what we know we know our mass number of romaine being 75 which is set equal to our mass number of our positron particle being zero and added to our mass number of our unknown product. New glide being A. And so solving for A. We would say that A. And let's use the color red a. is equal to 75. Moving forward. In our solution, we want to figure out the atomic number of our unknown product new glide. So plugging in our notes, we begin with the atomic number of bromine which we know is equal to our products. Where we have our atomic number of our positron particle being one which is added to our unknown atomic number of our product, new Clyde being Z. So solving for Z, we would say that Z is equal to 35 minus one and so Z is equal to 34. And so we would refer to our periodic table and see that on our periodic table. Atomic number 34 corresponds to the atoms selenium. And so now we can write out our full bounce nuclear equation where we have roaming 75 with with its atomic number 35 which undergoes a positron emission to produce a positron particle with the mass number of zero and atomic number plus one. And our product new glide, which would be our selenium with the atomic number 34 mass number 75. And our final answer is going to be this entire balanced nuclear equation that we've come up with. So I hope everything I explained was clear. If you have any questions, leave them down below and I will see everyone in the next practice video