Fill in the missing particles in each nuclear equation. b. _____ → 233 92 U + 0 -1 e

Hello everyone in this video. We want to identify this unknown species right over here in the equation. So let's go and get started. So in a radioactive decay or emission reaction, the radioactive particles ejected from the nucleus and from the product. So whenever we have a beta decay or beta emission, this occurs when an unstable nucleus ejects a beta particle to go ahead and create a new element. What a beta particle is has no atomic mass and is represented by an electron. So you can either write it like so or like So same thing for right. And the left on the top, we're gonna go ahead and have this be the mass number. And on the bottom we'll have our atomic number. Alright, So an element can be represented as very similarly we have our X let's say. And then A. And Z. So this X. Is going to be our element symbol. Same thing on top of each is the mass number on the bottom will be our atomic number. Alright, so kind of filling that in for equation then. So we have our X A Z. Go and bring down to our 1 87. On top bottom is 76 0. S. Plus that electron. All right. So, we can see here that we have these products. So our mass number of activities is equal to the mass number of products are mass number of the unknown is equal to the mask Number of beta particle plus the mass number of W. So in words or numbers then we have the a equals to Which is the mass number of either the unknown directions equaling or adding to zero. So that just means that automatically. Let's see we have 1 87 plus zero. That's 1 87. Now for our Z. Value. So this is a. Then we'll have C. Next at the atomic number react is equal to the atomic number of products. The atomic number unknown is equal to the atomic number of beta particle plus atomic number of new elements. So our atomic number on noon is Z. That's equal to the atomic number of beta particle which is negative one. The atomic number of new elements is 76. So negative one plus 76 is 75. The atomic number now that we have soft for it. We can go ahead and look at the P. R. A. Table and we see that for 75 that's going to be this uranium elements which has the symbol of our eve. Let's go ahead and write out our balanced nuclear equation then. So we have this R. E. On top is 1 87. Bottom is 75. This goes ahead to have 1 76 0. S. Plus the electron. Alrighty. And this is going to be my final answer for this question. Thank you all so much for watching

Ch.20 - Radioactivity and Nuclear Chemistry

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Ch.20 - Radioactivity and Nuclear Chemistry

Problem 36b

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Chapter 20, Problem 36b

Fill in the missing particles in each nuclear equation. b. _____ → ²³³₉₂U + ⁰_-1e

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Identify the type of nuclear reaction involved. In this case, the presence of an electron (\( ^0_{-1}e \)) suggests a beta decay process.

In beta decay, a neutron in the nucleus is converted into a proton, and a beta particle (electron) is emitted. This increases the atomic number by 1 while the mass number remains unchanged.

Given the product \( ^{233}_{92}U \), determine the original element by subtracting 1 from the atomic number of uranium (92) to find the atomic number of the parent element.

The parent element has an atomic number of 91, which corresponds to protactinium (Pa) on the periodic table.

Write the complete nuclear equation: \( ^{233}_{91}Pa \rightarrow ^{233}_{92}U + ^0_{-1}e \).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Nuclear Reactions

Nuclear reactions involve changes in an atom's nucleus and can result in the transformation of one element into another. These reactions are characterized by the emission or absorption of particles, such as alpha particles, beta particles, or gamma rays. Understanding the type of nuclear reaction is crucial for predicting the products formed and the particles involved.

Beta Decay

Beta decay is a type of radioactive decay in which a neutron in an atomic nucleus is transformed into a proton, emitting a beta particle (an electron or positron) in the process. This transformation increases the atomic number of the element by one while keeping the mass number unchanged. Recognizing beta decay is essential for filling in missing particles in nuclear equations.

Mass and Charge Conservation

In nuclear reactions, both mass and charge must be conserved. This means that the total mass number and the total charge before the reaction must equal those after the reaction. When solving nuclear equations, it is important to account for the particles involved to ensure that these conservation laws are satisfied, allowing for the correct identification of missing particles.