Sketch a voltaic cell for each redox reaction. Label the anode and cathode and indicate the half-reaction that occurs at each electrode and the species present in each solution. Also indicate the direction of electron flow.
b. 2 H⁺(aq) + Fe(s) → H₂(g) + Fe²⁺(aq)
c. 2 NO₃^–(aq) + 8 H⁺(aq) + 3 Cu(s) → 2 NO(g) + 4 H₂O(l) + 3 Cu²⁺(aq)

Question

Sketch a voltaic cell for each redox reaction. Label the anode and cathode and indicate the half-reaction that occurs at each electrode and the species present in each solution. Also indicate the direction of electron flow.
b. 2 H⁺(aq) + Fe(s) → H₂(g) + Fe²⁺(aq)
c. 2 NO₃^–(aq) + 8 H⁺(aq) + 3 Cu(s) → 2 NO(g) + 4 H₂O(l) + 3 Cu²⁺(aq)

b. 2 H⁺(aq) + Fe(s) → H₂(g) + Fe²⁺(aq)

c. 2 NO₃^–(aq) + 8 H⁺(aq) + 3 Cu(s) → 2 NO(g) + 4 H₂O(l) + 3 Cu²⁺(aq)

Accepted Answer

everyone's on this problem. We're given this, we actually right over here, we're trying to determine the cattle and and and have reactions, we also need to draw the electrochemical cell label it correctly and show the direction of the flow of electrons and ions. So from my cathode side which is where reduction happens. This half reaction is when H N 02 which is a crisis reacts with our age plus. Which of course since it's an ion with reacting with one electron, this gives us an O. In its gaseous state As well as H 20 in its liquid state. The standard reduction potential for this Is equal to 0.983V. Then we have our A. Node. And this is where of course the oxidation happens. So this reaction is the A. G. In its solid state reacting with our cl minus its across state to yield R A g C L, which is a solid. The standard reduction potential here is going to be equal to negative 0.2 to two volts. So these half reactions as well as their respective center reduction potential values are given to either in textbook given to bear professor or you can even be found online. So these are just the values and equations that I have. So for my sl value, we're gonna go ahead and calculate this in black is equal to just both over your standard reduction potentials. From both half reactions. So we have the 0.983 volts reacting with the negative 0.2 to two volts putting this into my calculator, I get them I. E. Cell value is 0.761 volts. So given our finding this value, then we see that this sl value is going to be greater than zero because it's a positive number. So this is a galvanic cell. In a galvanic cell. The annan is the negative terminal, while the cathode is the positive terminal. So electrons flow from the channel to the catholic. A gangbang. Sell also requires a salt bridge such as K C. L. So we can use an inert electrodes such as um P. T. So that's platinum to conduct electrons to the cathode have cell. So taking a look at the options of A. And B. We can see then that B is going to be our best fit for this answer. So my final answer then it's going to be as your choice be.

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