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Ch.19 - Electrochemistry

Chapter 19, Problem 79

Make a sketch of a concentration cell employing two Zn/Zn2+ half-cells. The concentration of Zn2+ in one of the half-cells is 2.0 M and the concentration in the other half-cell is 1.0x10^-3 M. Label the anode and the cathode and indicate the half-reaction occuring at each electrode. Also indicate the direction of electron flow.

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Hello everyone today. We are being asked to identify the following cells or which one of them represents? A concentration cell employing to lead to lead two plus have cells with concentrations of 1.5 molar and point to one molar. So the first thing I wanna do is they want to recall some principles in that at the node we have oxidation occurring or a loss of electrons and so that half reaction would look like our lead solid with an arrow followed by lead, two plus ions and two electrons. This denotes that we lost two electrons. Another important factor to note is that at the cathode we have reduction and so that's gonna be gaining electrons. So for oxidation we said losing electrons reduction we are gaining electrons And that half reaction is going to look like our lead two plus Aquarius Plus two electrons which denotes that we are gaining those which will give us our lead solid. And so if we go through these answer choices, the only one to correctly match that up is answer choice. C. We see that at the a note here we are losing electrons, electrons are flowing away and at the cathode our lead we have that our electrons are reducing that metal lead. And so the concentrations are also going to be flowing from a higher concentration to or a lower concentration to a higher concentration until they are in equilibrium. I hope this helped. And until next time