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Ch.17 - Aqueous Ionic Equilibrium
Chapter 17, Problem 62

Two 25.0-mL samples, one 0.100 M HCl and the other 0.100 M HF, are titrated with 0.200 M KOH. a. What is the volume of added base at the equivalence point for each titration?

Verified step by step guidance
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Step 1: Identify the reaction for each titration. For HCl, the reaction is HCl + KOH -> KCl + H2O. For HF, the reaction is HF + KOH -> KF + H2O.
Step 2: Calculate the moles of acid in each sample. Use the formula: moles = concentration (M) * volume (L). For both HCl and HF, moles = 0.100 M * 0.025 L.
Step 3: Determine the moles of KOH needed to reach the equivalence point. At the equivalence point, moles of KOH = moles of acid, since the reaction is a 1:1 stoichiometry.
Step 4: Calculate the volume of KOH solution required to provide the necessary moles of KOH. Use the formula: volume (L) = moles of KOH / concentration of KOH (M).
Step 5: Convert the volume of KOH from liters to milliliters by multiplying by 1000, as the final answer should be in mL.