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Ch.17 - Aqueous Ionic Equilibrium
Chapter 17, Problem 8

A 20.0-mL sample of a 0.125 M diprotic acid (H2A) solution is titrated with 0.1019 M KOH. The acid ionization constants for the acid are Ka1 = 5.2 * 10^-5 and Ka2 = 3.4 * 10^-10. At what added volume of base does each equivalence point occur?

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1
Calculate the moles of the diprotic acid (H2A) using the initial concentration and volume: \( \text{moles of } H_2A = 0.125 \text{ M} \times 0.0200 \text{ L} \).
Determine the moles of KOH needed to reach the first equivalence point, where all \( H_2A \) is converted to \( HA^- \). This is equal to the initial moles of \( H_2A \).
Calculate the volume of KOH solution required to reach the first equivalence point using the moles of KOH and its concentration: \( \text{Volume of KOH} = \frac{\text{moles of KOH}}{0.1019 \text{ M}} \).
Determine the moles of KOH needed to reach the second equivalence point, where all \( HA^- \) is converted to \( A^{2-} \). This is twice the initial moles of \( H_2A \).
Calculate the total volume of KOH solution required to reach the second equivalence point using the moles of KOH and its concentration: \( \text{Total Volume of KOH} = \frac{\text{moles of KOH for second equivalence point}}{0.1019 \text{ M}} \).