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Ch.17 - Aqueous Ionic Equilibrium
Chapter 17, Problem 11

After a 120.0-mL sample of a solution that is 2.8 * 10^-3 M in AgNO3 is mixed with a 225.0-mL sample of a solution that is 0.10 M in NaCN and the solution reaches equilibrium, what concentration of Ag+(aq) remains?

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1
Determine the initial moles of AgNO3 by using the formula: \( \text{moles} = \text{concentration} \times \text{volume} \). Convert the volume from mL to L before calculation.
Determine the initial moles of NaCN using the same formula: \( \text{moles} = \text{concentration} \times \text{volume} \). Again, convert the volume from mL to L.
Write the balanced chemical equation for the reaction between AgNO3 and NaCN. The reaction is: \( \text{Ag}^+ + 2\text{CN}^- \rightleftharpoons [\text{Ag(CN)}_2]^- \).
Calculate the limiting reactant by comparing the mole ratio from the balanced equation with the initial moles of reactants.
Use the stoichiometry of the reaction to determine the change in moles of \( \text{Ag}^+ \) at equilibrium, and then calculate the concentration of \( \text{Ag}^+ \) by dividing the remaining moles by the total volume of the solution in liters.