For each strong acid solution, determine [H3O+], [OH-], and pH. b. 0.015 M HNO3

Video transcript

Hey everyone, we're asked what is the ph concentration of hydrogen ions and the concentration of hydroxide ions for a 0.732% per clark acid by mass of a strong acid solution with a density of 1.2 g per meal leader since we have a strong acid, we know that this is going to dissociate completely and we can go ahead and assume that we have 100 g of solution. This will also make it easier for us to convert from percentage Instagram's first. Taking our 0.732%, we can convert this into grams of solution per g of solution. We then want to use the density for our dimensional analysis. So we have 1.02 g of solution per one mil liter of solution. Now, using the molar mass of per clark acid, we know that we have 100.46 g of per clark acid Per one mole of per caloric acid. Next we want to convert our milliliters of solution into liters of solution for our denominator. So we know we have 10 to third milliliters of solution for one liter of solution. So when we calculate this out and cancel out all of our units, we end up with a polarity of 0. moller a perk Lorik acid, which is going to be the concentration of our hydro ni um ions. Now let's go ahead and write out our reaction. So we have our per caloric acid and this is going to react with our water. Since it is a strong acid, it will completely dissociate to those hydro ni um ions and those per chlorine ions. Now let's go ahead and calculate our ph we know that our ph is the negative log of our hydro ni um ion concentration. So, plugging that in, we get the negative log of 0.07432, which will get us to a ph of 1.129. And lastly, we want to calculate the concentration of our hydroxide ions and we're going to use our KW, which is one times 10 to the negative 14 And divide that by the concentration of hydrogen ions which was 0. Molar. This will get us to a concentration of 1.35 times 10 to the - Mueller. And these are going to be our final answers Now, I hope this made sense. And let us know if you have any questions