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Ch.14 - Chemical Kinetics
Chapter 14, Problem 57b

The half-life for the radioactive decay of U-238 is 4.5 billion years and is independent of initial concentration. If a sample of U-238 initially contained 1.5⨉1018 atoms when the universe was formed 13.8 billion years ago, how many U-238 atoms does it contain today?

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Identify the given values: the half-life of U-238 is 4.5 billion years, the initial number of atoms is 1.5 \times 10^{18}, and the time elapsed is 13.8 billion years.
Use the formula for radioactive decay: N(t) = N_0 \times (1/2)^{t/t_{1/2}}, where N(t) is the number of atoms remaining, N_0 is the initial number of atoms, t is the time elapsed, and t_{1/2} is the half-life.
Substitute the given values into the formula: N(t) = 1.5 \times 10^{18} \times (1/2)^{13.8/4.5}.
Calculate the exponent: 13.8/4.5 to determine how many half-lives have passed.
Evaluate the expression to find the remaining number of U-238 atoms, N(t).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Radioactive Decay

Radioactive decay is the process by which an unstable atomic nucleus loses energy by emitting radiation. This decay occurs at a predictable rate characterized by the half-life, which is the time required for half of the radioactive atoms in a sample to decay. For U-238, this half-life is 4.5 billion years, meaning that after this period, only half of the original amount of U-238 remains.
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Rate of Radioactive Decay

Half-Life

Half-life is a fundamental concept in nuclear chemistry that quantifies the time it takes for half of a radioactive substance to decay. It is a constant for each isotope and does not depend on the initial amount of the substance or environmental conditions. Understanding half-life is crucial for calculating the remaining quantity of a radioactive isotope after a given period, as seen in the decay of U-238 over billions of years.
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Exponential Decay

Exponential decay describes the process where a quantity decreases at a rate proportional to its current value. In the context of radioactive decay, the number of remaining atoms decreases exponentially over time, following the formula N(t) = N0 * (1/2)^(t/T), where N0 is the initial quantity, t is the elapsed time, and T is the half-life. This concept is essential for calculating the remaining U-238 atoms after 13.8 billion years.
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Related Practice
Open Question
The decomposition of XY is second order in XY and has a rate constant of 7.02 * 10^-3 M^-1 s^-1 at a certain temperature. b. How long will it take for the concentration of XY to decrease to 12.5% of its initial concentration when the initial concentration is 0.100 M? When the initial concentration is 0.200 M? c. If the initial concentration of XY is 0.150 M, how long will it take for the concentration to decrease to 0.062 M? d. If the initial concentration of XY is 0.050 M, what is the concentration of XY after 5.0 * 10^1 s? After 5.50 * 10^2 s?
Textbook Question

The decomposition of XY is second order in XY and has a rate constant of 7.02⨉10-3 M-1• s-1 at a certain temperature. a. What is the half-life for this reaction at an initial concentration of 0.100 M?

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Textbook Question

The half-life for the radioactive decay of U-238 is 4.5 billion years and is independent of initial concentration. How long will it take for 10% of the U-238 atoms in a sample of U-238 to decay?

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Textbook Question

The half-life for the radioactive decay of C-14 is 5730 years and is independent of the initial concentration. How long does it take for 25% of the C-14 atoms in a sample of C-14 to decay?

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Textbook Question

The half-life for the radioactive decay of C-14 is 5730 years and is independent of the initial concentration. If a sample of C-14 initially contains 1.5 mmol of C-14, how many millimoles are left after 2255 years?

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Textbook Question

The diagram shows the energy of a reaction as the reaction progresses. Label each blank box in the diagram.

a. reactants b. products c. activation energy (Ea) d. enthalpy of reaction (ΔHrxn)

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