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Ch.13 - Solutions
Chapter 13, Problem 51b

An aqueous NaCl solution is made using 112 g of NaCl diluted to a total solution volume of 1.00 L. Calculate the molality of the solution. (Assume a density of 1.08 g/mL for the solution.)

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Molarity and Molality

Molarity (M) is defined as the number of moles of solute per liter of solution, while molality (m) is the number of moles of solute per kilogram of solvent. Understanding the difference is crucial for calculations involving concentrations, especially when dealing with solutions where temperature and volume may affect molarity but not molality.
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Calculating Moles from Mass

To find the number of moles of a substance, you can use the formula: moles = mass (g) / molar mass (g/mol). For NaCl, the molar mass is approximately 58.44 g/mol. This calculation is essential for determining the concentration of the solute in the solution.
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Density and Volume Relationships

Density is defined as mass per unit volume (g/mL or g/cm³). In this problem, the density of the solution is given as 1.08 g/mL, which allows us to convert the total volume of the solution into mass. This conversion is necessary to calculate the mass of the solvent (water) for determining molality.
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