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Ch.10 - Chemical Bonding II: Molecular Shapes & Valence Bond Theory

Chapter 10, Problem 86d

The genetic code is based on four different bases with the structures shown here. Assign a geometry and hybridization to each interior atom in these four bases. d. guanine

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Hey everyone we're asked to identify the geometry and hybridization of each atom in the ring in the structure of your cell. Which is one of the four nuclear bases in RNA. And they've given us a structure below. Starting off with our first one, we have our carbon. When we count the electron groups surrounding our carbon, we have 12 and three. So we have three groups. This means that we have a hybridization of sp two and a geometry of tribunal planer. Next looking at our second one, we have a nitrogen counting the number of groups. We have 123 and four. We have four groups Because we have four groups. This means our hybridization is s. p. three and our geometry is going to be tetra federal. Next looking at our third carbon, we have groups surrounding it because we have three groups. Again we have S. P two as our hybridization and tribunal planer as our geometry. Next looking at our 4th 1, we have a carbon as well counting the groups. We have 12 and three. Again we have three groups Which will get us to s. p. two. And tribunal planer as our geometry. Looking at our fifth carbon, we have 12 and three. We have three groups surrounding it, which means we have s. p. two. And again, Tribunal plainer lastly looking at our six atom, we have nitrogen counting the number of groups. We have 123 and four. We have, four electron groups. Which means we have a hybridization of S. P three and a geometry of tetra. He'd rel, And this is going to be our final answers for this question. So I hope that made sense and let us know if you have any questions.