Acetone (nail polish remover) has a density of 0.7857 g/cm 3 . a. What is the mass in g of 28.56 mL of acetone? b. What is the volume in mL of 6.54 g of acetone?

Hey everyone. So here we're told the density of ethanol is 0.789 g per mil leader. And for part A. We need to determine the mass when given a 15.8 ml volume. And we need to express the answer in terms of 466 for B. We are given the grams of ethanol. We need to find the volume also in terms of four significant figures. Alright, so let's start out with part A. We have 15.8 mls. We take our density, which is one middle leader 10.789 g. So here mls cancel out and we'll have our grams, which comes out to 12.47 g. As our final answer For B were given 5.63 g. Because grams need to be canceled out. I need to flip my density where the grams are here on the bottom now and mls on the top here. When I work this out, that's gonna give me 7.136 mls as my final answer. So these represent the answers for both A and B respectively.

Ch.1 - Matter, Measurement & Problem Solving

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Tro 4th Edition

Ch.1 - Matter, Measurement & Problem Solving

Problem 70

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Chapter 1, Problem 70

Acetone (nail polish remover) has a density of 0.7857 g/cm³. a. What is the mass in g of 28.56 mL of acetone? b. What is the volume in mL of 6.54 g of acetone?

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**Step 1:** Understand the relationship between mass, volume, and density. The formula to use is: \( \text{Density} = \frac{\text{Mass}}{\text{Volume}} \).

**Step 2:** For part (a), rearrange the formula to solve for mass: \( \text{Mass} = \text{Density} \times \text{Volume} \).

**Step 3:** Substitute the given values for density (0.7857 g/cm³) and volume (28.56 mL) into the formula to find the mass. Remember that 1 mL = 1 cm³.

**Step 4:** For part (b), rearrange the formula to solve for volume: \( \text{Volume} = \frac{\text{Mass}}{\text{Density}} \).

**Step 5:** Substitute the given values for mass (6.54 g) and density (0.7857 g/cm³) into the formula to find the volume.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Density

Density is defined as the mass of a substance per unit volume, typically expressed in grams per cubic centimeter (g/cm³). It is a crucial property that helps determine how much mass is contained in a given volume of a substance. In this question, the density of acetone is used to convert between mass and volume, allowing us to calculate the mass of a specific volume of acetone and vice versa.

Mass-Volume Relationship

The mass-volume relationship is a fundamental concept in chemistry that describes how mass and volume are interrelated through density. The formula used to express this relationship is: mass = density × volume. This relationship is essential for solving problems that involve converting between mass and volume, as seen in the calculations for acetone in the question.

Unit Conversion

Unit conversion is the process of converting a quantity expressed in one set of units to another set of units. In chemistry, it is often necessary to convert between different units of mass (grams) and volume (milliliters or liters). Understanding how to perform these conversions accurately is vital for solving problems involving measurements, such as calculating the mass of acetone from its volume and density.

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Conversion Factors

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Acetone (nail polish remover) has a density of 0.7857 g/cm3. a. What is the mass in g of 28.56 mL of acetone? b. What is the volume in mL of 6.54 g of acetone?

Verified Solution

Key Concepts

Density

Mass-Volume Relationship

Unit Conversion

Acetone (nail polish remover) has a density of 0.7857 g/cm³. a. What is the mass in g of 28.56 mL of acetone? b. What is the volume in mL of 6.54 g of acetone?