What shape do you expect for molecules that meet the following descriptions? (a) A central atom with two lone pairs and three bonds to other atoms (b) A central atom with two lone pairs and two bonds to other atoms (c) A central atom with two lone pairs and four bonds to other atoms

Video transcript

well everyone in this video we're trying to do is determine the shape of the molecules, based on three different descriptions. So we have three different shapes. So the first one, it reads too long pairs and four atoms are connected to the central atom. So here we're determining the first one. So we said that we have two lone pairs. So to simplify that to be LP and we have four bonds because we have four items and they need four bonds to be connected to it. So if we add these two, so just two and four, we have a total of six electron groups. So that's just because we have two lone pairs and then the four items are connected to the one item that we're focusing on. And with the six election groups, of course we have two of them being lone pairs. So here I was thinking about the vesper theory and if we have sex election groups and two of them being lone pairs, then this is going to be square planer. Alright, so that's going to be one of my answers. Alright, now, for the second one here, this description reads three lone pairs and two atoms are connected to the central atom. So now in this case we have three lone pairs and two bonds because we have two atoms attached to the central atom. So of course three plus two is equal to five. So here we have five electron groups. And of course we have three of them being lone pairs. Now taking a look at vesper theories. If we have five electron groups total, but three of them are going to be lone pairs. This shape here is going to be linear. That's my answer for the second statement here, and for the third statement, I'll do this in blue here. We have the one lone pair and five atoms, so we have one lone pair and five bonds. Of course this equals to six electron groups. And here, unlike the first statement that we have just read, we have one lone pair instead of two. So look at Jasper theory, if we have six lecture groups and one long parent, the sheep for this is going to be square Lamido. This concludes my final answer for this problem.