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Ch.8 - Covalent Compounds: Bonding Theories and Molecular Structure

Chapter 8, Problem 70

What is the hybridization of the B and N atoms in borazine, what are the values of the B¬N¬B and N¬B¬N bond angles, and what is the overall shape of the molecule?

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Hello everyone. So in this video we want to determine the hybridization of auction and dimethyl ether. So this molecule here as well as determine the molecular geometry around the auction adam and the bond angle between dark carbon auction carbon bond. So first we go ahead and determine the hybridization of auction. So we see here from the structure that we have two bonds and two lone pairs. So spread this out. So here determining the hybridization. So again we have two bonds and two lone pairs. So we have a total of four electron groups. If we have four electron groups running are essential item then we have sp three hybridization. So that's going to be what the hybridization is. So that's one of our answers. Next. We can go ahead and determine the molecular geometry of auction. All right. So we have here like we said two bonding groups as well as two lone pairs. And if we have two bonds and two lone pairs then that means the molecular geometry is going to be bent. Alright now the last thing we have to go ahead and determine is going to be our bond angle. So we said our geometry is going to be bent. So again, we're determining bond angle. All right. So we said the molecular geometry is bent and take into consideration our CH three groups here. So these mental groups here on both ends of our auction and um the angle is actually going to be 110°. So again, we're taking into consideration for upon angle not only the molecular geometry of being bent but also our groups are hanging off our auction atoms So the spawn angle is equal to 110°. The hybridization is s. p. three and the molecular geometry is going to be bent.