Use the chemical structure for Tagamet, a drug used to treat peptic ulcers and heartburn, to answer questions 8 and 9.

Which orbitals overlap to form bond 1? (LO 8.5) (a) s bond: N 1sp22 with C 1sp22; p bond: N (p) with C (p) (b) N 1sp22 with C 1sp22 (c) s bond: N 1sp22 with C 1sp22; p bond: N 1sp22 with C 1sp22 (d) s bond: N (sp) with C 1sp22; p bond: N (p) with C (p)

Video transcript

Hello. Everyone in this video, we want to identify the orbital overlap to form bonds one here between the carbon and nitrogen as well as bond number two that connects nitrogen and carbon and a single bond and we can go ahead and ignore residents in the structure. And this problem. So for a bond one we see here that carbon has three bonding groups. Just simplified bonded groups to BBg because it has three different bonding groups. And this is an sp two hybridization. And for nitrogen here we see that we have two bonding groups. So to be G. As well as one lone pair, which is a simplified to L. P. So we have 12 3 electron groups. That's an sp two hybridization. So for bond one year we have a double bond. So we need to consider the sigma as well as the pi bond. So our carbon nitrogen sigma bond here, it's an interaction between the carbons S. P. Two and the nitrogen sp two. Now for the carbon nitrogen pi bond here, we're dealing with the pi bonds of each atom. So we have carbons pi bond or P orbital reacting with nitrogen is p orbital. So that's going to be the interactions between Bond one. Next is going to be between bond to and this is just the single bonds between the nitrogen and carbon. So this carbon in our case has four bonding groups. That means sp three hybridized. Now for nitrogen we here see we have three bonding groups so that's three B. G. And this is reacting with one long pair as well. So this total of four electron groups, that's an Sp three hybridization. So carbon nitrogen sigma bond Interacts or occurs because we're having our carbons SP three Acting with nitrogen sp three orbital. So these highlight answers are going to be my final answer for this problem.