Identify the fourth-row elements, X, that form the following compounds. (a)

Video transcript

Everyone in this video trying to identify the elements found in the 4th row of the periodic table. That corresponds to this unknown x. So we can go ahead and kind of break down the slower structure. So we see here of the central item here, we have five bonds right over here. So because we have these five bonds, each bond gives us two electrons. So five times two is 10. And then for our five atoms are five bro means We have three lone pairs on them. So again, that's just five runnings and then each long pair contains two electrons. So three times two is six. So how many electrons that come from our terminal bromine atoms is using the calculation of five times six, which is equal to 30 electrons. So now we can just go ahead and sum up the 10 electrons in the 30 and that gives us a total count of 40 vance electrons in the structure. So browning here has seven valence electrons and that's just from the three lone pairs. So that gives us six electrons. And this bond here is being shared and of course we just know that one bond has two electrons. So one will be for our browning and one will be for unknown X. So browning does have seven valence electrons each. So seven valence electrons per bromine atom. We have five brahmins here and sometimes five is electrons. So that means the remaining five electrons will be responsible by the central item of X. And we can go ahead and look at all the different um elements found in the fourth row. And the one that's in Group five A will give us five bands electrons. So we look at the PR table that's going to be our element arsenic, which is answer choice C. In this problem.