Draw orbital-filling diagrams for atoms with the follow-ing atomic numbers. Show each electron as an up or down arrow, and use the abbreviation of the preceding noble gas to represent inner-shell electrons. (b) Z = 56

Video transcript

Hello everyone today. We are being given the falling problem, draw an orbital filling diagram for the element of atomic number 28. Use up and down arrows to show electrons to represent the inner shell electrons use the symbol of the preceding noble gas. So essentially we're being asked to find the noble gas configuration of our Atomic # 28. So let's find the element. So the element with the atomic number of according to the periodic table is going to be nickel And Nickel is in the 4th period or the 4th row of the periodic table. And so if you look at the preceding noble gas, so we have a pre seeding noble gas, abbreviated MG. That is going to be argon and argon has 18 electrons in period three. So this denotes that the electrons that remain. So the remaining electrons are going to be that 28 that we have because the atomic number is equal to the number of electrons that we have. And so we have 28 electrons and nickel minus the 18. And those are gone Gives us 10 electrons left to work with. And so we have to essentially divide those 10 electrons into the remaining sub shells. So R S sub shell can hold two electrons. Our p sub shell can hold six electrons and R D sub shell can hold 10 electrons. As for an F orbital that can hold a maximum of 14 electrons but we will not be dealing with that in this problem. And so if we have our orbital diagram, we have argon here followed by our four s orbital since we were in period four, we're gonna use up and down arrows to denote electrons. So we're gonna fill that forest orbital which can hold two electrons as we said. And then we have our three D orbital which is going to have five orbital's because each orbital, each individual orbital can hold a maximum of two electrons And so five times 2 gives us 10 electrons total. And so to fill in the remaining, we have to determine what we're going to do with these 10 electrons. So we have our noble gas configuration of argon, We have our four S 2. We must now go into our three D orbital because our D orbital is always going to be one less than our four orbital or our period. For example, if we're in the four s we're going to have three D, five s, four D And so on, and so forth. So we have forest to three D. And then we have to use those remaining 10 electrons. And by the way, these exponents are going to represent the electrons that we have. So those are going to equal our 10 that we have left over. And so we have to put those remaining eight electrons in this diagram. And according to Hunt's rule, we must put one electron in each orbital before pairing them up. And so we're going to have one going up 2345. We're going to pair them up 678. And so this is going to be our orbital filling diagram for our atomic number 28 which is nickel. And with that, we have answered the question overall, I hope that this helped, and until next time.