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Ch.5 - Periodicity & Electronic Structure of Atoms

Chapter 5, Problem 115

Cyclooctatetraene dianion, C8H8 2-, is an organic ion with the structure shown. Considering only the p bonds and not the s bonds, cyclooctatetraene dianion can be described by the following energy diagrams of its p molecular orbitals:

(d) Based on your MO energy diagram, is the dianion paramagnetic or diamagnetic?

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Hello everyone something. This video we're trying to do is determine if our molecule C four H minus is para mimetic or biomimetic. So given the structure of this ion here, let's go ahead and actually count our electrons. So of course we have our hidden high regions in this molecule. So I'll just go ahead and fill those in. So we can see that each carbon here. So just each of these corners basically here is surrounded by three atoms. So let's go ahead actually fill one of them. So we'll have carbon here. That means we're connected to another carbon, another carbon and the hydrogen. So two carbons and one hydrogen that makes three atoms being connected to the central carbon here. So if we do that or if we have that. So again we have three atoms surrounded which means that this carbon in the middle here, that's going to be SP two hybridized with one p orbital. So if you have that then we'll have four of these carbons, each with one Of our P. orbital's. That gives us total of four pi electrons. And then we can see here that these two are two minus charge means that we have gained two electrons. So because of that we go ahead and actually add this in as well. That gives us a total of six. Hi electrons Using this information will go ahead and fill out this diagram here, let's go ahead and do so again we're putting in six pi electrons. So I have 12345 and six. So let's go ahead and recall what paramedic and geomagnetic means. So dia magnetic is when there's no one paired electrons, meaning everything is paired. On the other hand, we have para magnetic and that's when we have unpaid electronics. Alright, so taking a look at what we just filled in here. Do we see any unpaid electrons? It seems that everything is paired. Therefore we have a diabetic and ion. So our final answer then is that C four H 42 minus is dia magnetic. And this right here is going to be my final answer for this problem. Thank you all so much for watching.